Thanks for the help.

I'd forgotten I'm on someone else's wi fi at the moment. It's their content blocker. Seems to be a common problem with Vodafone. So I'll wait and see if the OP wants my diagram before tinkering with the settings.

Bob

]]>Thank you all so much for taking the time to help out. I do appreciate. It appears there is no solution for the question. There must have been an error in whatever book from which my mate sent me that question.

Regards,

math9maniac

Welcome to the forum.

This problem came up ages ago so I've mostly forgotten it. Some other posters provided quicker solutions than mine; that's fine; I never said mine was the only one nor that it was quick. The OP was happy to be taught some new maths along the way which I was happy to do.

PQRC is a sloping plane. So QR isn't a continuation of PQ. Not sure what you mean here.

Bob

]]>What is ?

Thank you very much now I got it.

]]>Need not bother I solved it.]]>

B

]]>Thanks for posting this. Have you considered creating an account with us?

For reference, the sequence is:

4, 4, 341, 6, 4, 4, 6, 6, 4, 4, 6, 10, 4, 4, 14, 6, 4, 4, 6, 6, 4, 4, 6, 22, 4, 4, 9, 6,

and we're asked to find the next two terms. Perhaps this will give you a hint:

**4**, **4**, 341, 6, **4**, **4**, 6, 6, **4**, **4**, 6, 10, **4**, **4**, 14, 6, **4**, **4**, 6, 6, **4**, **4**, 6, 22, **4**, **4**, 9, 6,

Remember, the triangle inequality theorem states that the sum of any two sides of a triangle must be greater than the length of the third side.

In #7, only B would be appropriate.

Use the same analogy.

]]>Welcome to the forum!

If there is a single question, or two, for which you need help, post here.

Usually, hints are given.

For adding photograph, use tags [ img] and [ /img].

For example, is a diagram of Altitude in MathsIsFun.

]]>2) Use the substitution a=x2+2y+1, into the top equation.

Rearrange and square to get rid of the root, and get a quadratic in a.

Solve to get a value (or values) for x2+2y+1.

Substitute the bottom equation to get rid of the y and get a quadratic for x.

3) Very similar to 2, I'll let you work out the details.

4) Simply square the top equation.

Rearrange to get rid of the denominator, you should have a quadratic expression in x and y, which factorizes.

Substitute the solution into the bottom equation to get another quadratic in x (or y) and solve.

For example, if I get a number in the range {9K5 to 10K5} for the value of a resistor, I would simply select the 10K resistor. Obviously, the designed circuit should be made to work properly even if the exact value of the resistor in use is also a bit outside this range.

On the other hand, solving math problems could be a target if it is for fun... as testing the level of one's logic (logical reasoning).

]]>I'm struggling a bit with your working. The octagon consists of 8 isosceles triangles. If 'a' is the height of one of these then I agree with your answer. So next I worked out the area of 8 of these triangles 8 times 2.5 times a. Where did 40 come from ?

Please re-post your working with some notes at each line to say what you are calculating.

Bob

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