Bob

]]>This diagram appears elsewhere as I have taken the trouble to do this in a 'child' suitable way. I also gave a link to a MIF page that answers the teacher's question.

Please check your other posts and do not post the same thing wtice.

Bob

]]>12. √576

as an example.

576 = 2 x 288 = 2 x 2 x 144 = 2 x 2 x 2 x 72 = 2 x 2 x 2 x 2 x 36 = 2 x 2 x 2 x 2 x 2 x 18 = 2 x 2 x 2 x 2 x 2 x 2 x 9 = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3

You keep dividing by prime factors until the resulting multiplication is all primes. http://www.mathsisfun.com/prime-factorization.html

Now you can see if the number is a perfect square:

2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 = (2 x 2 x 2 x 3) x (2 x 2 x 2 x 3) = 24 x 24

Bob

]]>Hurrah! At last you have given me a diagram for the shuffleboard. Now we can make some progress.

You have used 'postimage' for the diagram. I have a problem with that. (1) The image shows on a page that is full of adverts. MIF has to keep its pages suitable for children to view. Some of the adverts I saw are not. I use imgur for my images. The posters to imgur sometimes post unsuitable material too, but the link I provide on my posts is to the image only; you would have to go to the imgur site to see other material. That makes it better for MIF. So I have copied your diagram to my imgur account and replaced your image link with mine. I'll do the same with your other post when I get time. But I'd prefer that you do this yourself as it takes time.

Here's how to get a picture (on its own) into a thread:

http://www.mathisfunforum.com/viewtopic … 17631&p=23 post number 1686

Now to the problem.

3. What are the dimensions of the 1 rectangle?

4. What are the measurements of one of the 5 rectangles?

Both these can be worked out with some simple arithmetic.

You're told that the '1' is twice the width of the '2' so that's easy to calculate.

If you then add up all the widths and subtract from 108, you'll have the width of the open (non scoring) space.

The '4' space is 15 top to bottom, so subtracting from 30 will give you the remainder for the two '5s'. So divide that remainder by 2 to get the missing dimension of the '5'.

Now sketch the whole board and by length x width write in the area of every section. The overall area is 30 x 108.

The probability of landing in any space is (area of that space) divided by (overall area)

Hope that helps.

Bob

]]>20! * 12! = x (mod 2012)

Some useful facts i have discovered:

1) 7 * 8 * 9 = 1 (mod 503)

2) 20! * 12! = 13 * 17 * 19 mod(503)

I have been trying to solve this problem for a long time. If you can find the answer, could you please show the step by step solution? Thank you for your help.

]]>Constructing a 30 degree angle is fairly straight forward but what if it's another angle, θ. Find F by (1) Drawing a line straight up from A; (2) Draw a line from B,

angle 90 - θ; (3) where these lines cross is F with AFB = θ

Some other ways of drawing the ellipse. We're used to using a compass to make a circle or an arc. There's a similar way to make an ellipse. Tie a piece of string in a loop exactly AB + BC + CA long. Put two drawing pins into the paper at the focal points. Loop the string around both pins and pull tight with a pencil. Allow the pencil to track around the foci and it will draw an ellipse.

There is also a construction which fixes points on the perimeter of the ellipse. Then you join them with a smooth curve. It's about 50 years since I last used this technique so I'll have to do some hard thinking if you want to see how it's done

Bob

]]>http://hplgit.github.io/prog4comp/doc/p … ab025.html

Obviously, exact code will depend on what you're trying to solve.

B

]]>(1) I think it's only one as well. If the altitudes are AD and BE and they meet at G, then DGB = 60 and GDB = 90 implies DBG = 30.

BEC = 90 and CBE = 30 implies BCE (BCA) = 60.

(2) Work in progress.

Later edit: I am unable to draw a diagram for this at all. Let D be where the bisectors cross.

A + B < 180 implies DAB + DBA < 90. Therefore ADB > 90

Do you have a diagram?

Other post: I'm working on a method involving ellipses and circles. If successful I'll post on that thread later. Later edit: Done in other thread.

Bob

]]>.

Because it contains "math"?

I knew it.

]]>