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Second, well I think his butt is sore after sitting down there. So he wanna cross the street. BTW, do you know Crossy Road?

]]>-Bri

]]>#27. Sounds like funny bone. (7)

]]>Well, I just finished solving the puzzle again for a final check...and all is ok.

But - and wouldn't you know it! - of course I spotted a further improvement opportunity and have edited the puzzle again. The change mainly affects the class-number component and increases the difficulty level of its solution, but at the same time it fixes a clue that was a bit unsatisfactory but for which I hadn't been able to find a better alternative until now.

Latest revision:

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Yes, the given solution method is rather starter-ish.

A more satisfying solution exists, however, which by way of a nice mathematical formula in terms of *n* eliminates all that counting and will instantly display the answer for *n* (eg, *n*=12) days.

The formula can be found on the net, but, if you'd like to have a go at constructing it yourself, then here are a couple of hints (should you need them):

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This puzzle is also discussed here.

]]>Pick any 4-digit number at all (should not have the same digit throughout). Rearrange the digits to form as many 4-digit numbers as possible. From the range of numbers (including the one you first picked), subtract the least from the greatest. If the difference is a 2-digit number add the digits together.

The idea behind this is no matter what your answer will always be 9. Yes try it now.

Okay.

1234

1234 1243 1324 1342 1423 1432

2134 2143 2314 2341 2413 2431

3124 3142 3214 3241 3412 3421

4123 4132 4213 4231 4312 4321

4321

1234

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3087

Well, it's 4 digits but I'll go add it... 3+0+8+7 = 18 (1 + 8) = **9**.

Worth that 10 minute typing. BTW, the name of the topic reminds me of a book I borrow in the library at my school.

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