First of all, the rule is:

*USA* y = mx+b

*UK* y = mx+c

Work these out:

(a) (2,-1),(4,2)

(b) (-3,1),(-1,-1)

(c) (2,1),(6,1)

(d) (-1/2,1),(2,1/2)

(e) (0,4),(-2,1)

Have fun working them out~*

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]]>"Math is fun" with the back of my hand.]]>

I hope you don't mind me posting this - I'm doing some research into puzzle games and why people enjoy them at St Andrews University. If you have five minutes and could fill out the survey below it would be really appreciated. We're really struggling to find people outside the academic environment.

The survey is completely anonymous, there is the option to leave your email address at the end if you want to participate in a follow up study but it only applies if you are based in Scotland. (please still click the final arrow below the request though - otherwise your response may not be recorded!)

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Thank you so much!

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You are statistically more likely to choose a goat initially.

Therefore it is statistically better to change.

haha i came up with the EXACT same solution today...

]]>If 1500 tickets

I think the answer might be 1500 tickets because if 1500 tickets, then 1500 tickets!

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]]>If

a= 2,b= 1,c= 4, thenA= √(2+1·√ 4) = 2,B= √(2−1·√ 4) = 0,S=A+B= 2 ≠b.

Good work.

In this case, the original statement should be updated as:

"If their sum *A+B=S* comes out as a natural number, *S* equals *b* if *b* ≠ 1".

Thank you.

Added:

also *a* ≠ 0, *b* ≠ 0 and *c* ≠ 0

Welcome to the forum.

Good result. But I'm afraid it has been done before. This was, for a while, a GCSE maths project in the UK. You'd get a grade 'C' for what you have posted but would need to show the whole proof and try possible extensions to get an 'A'.

Bob

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