The two solutions in 519 are correct. Excellent, bobbym!

520. Find the coordinates of the end points A and B of the segment whose points of trisection are M(2,-1) and N(3,1).

]]>Construct a sequence with elements in S such that all terms are different. This should be possible because S is infinite. Now, because this sequence is bounded, it must have a convergent subsequence which is non-constant.

Hence, it follows that S' is non-empty.

]]>Does "Pseudo Compact" in this case the same as "Anti-Compact" ? Then how can we describe the "Pseudo-Compact" subsets of Real Numbers?

]]>How about too easy. That will take care of tary-try-tree-tri-trey.

]]>NOTE: These exercises refer to the material posted in

thisthread.#1

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Loopholes: There are always ways out of any predicament and no one knows that better than me... You posted this in Exercises, all of the above comments are basically for Help Me! If you know the answer and are posing this as a problem for others to solve then I will just blurt out the answer before anyone else does. I was the fastest in class, at work and just about anywhere else. True, I ain't 25 anymore but at 96 and toothless I will still take on any whippersnapper in a forum and on the trail.

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How would you use this information to construct an arbitrary number of limit points?

]]>I am sorry if you have been offended. I had every reason to believe you were pulling my leg.You only had given me the value of x=3 ,not chosen by me.

In addition taking dx=0.02 does not confirm to its being infinitesimal. So that may not be what is expected.]]>

Bob

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