<![CDATA[Math Is Fun Forum / Exercises]]>2016-06-29T17:46:26ZFluxBBhttp://www.mathisfunforum.com/index.php<![CDATA[Compute the solution:]]>Hi;

]]>http://www.mathisfunforum.com/profile.php?id=337902016-06-29T17:46:26Zhttp://www.mathisfunforum.com/viewtopic.php?id=21675&action=new<![CDATA[functional equation.]]>Yes, I really could see no use for such a head until the guys over here started a thread about typing with other than their fingers. I of course used my sharpened head and it was easy. It was then that I knew why I had been born...]]>http://www.mathisfunforum.com/profile.php?id=337902016-06-25T01:13:39Zhttp://www.mathisfunforum.com/viewtopic.php?id=23169&action=new<![CDATA[probability]]>Thanks Thickhead.]]>http://www.mathisfunforum.com/profile.php?id=1956022016-06-22T05:21:42Zhttp://www.mathisfunforum.com/viewtopic.php?id=23152&action=new<![CDATA[Solve the equation]]>]]>http://www.mathisfunforum.com/profile.php?id=2124862016-06-15T06:23:57Zhttp://www.mathisfunforum.com/viewtopic.php?id=22698&action=new<![CDATA[Boxes with disks.]]>]]>http://www.mathisfunforum.com/profile.php?id=2124862016-06-14T09:59:54Zhttp://www.mathisfunforum.com/viewtopic.php?id=22808&action=new<![CDATA[Quickies #4, Mathematics.]]>Hi;

I wished you would have told me that earlier because I just spent 2 days solving the problem with neither side starting first. That condition makes it a whole different problem.

]]>http://www.mathisfunforum.com/profile.php?id=337902016-06-13T22:48:23Zhttp://www.mathisfunforum.com/viewtopic.php?id=23118&action=new<![CDATA[Elementary Math Olympaid]]>I'm kinda busy at the moment, can't access my computer for the coming days... But I see some minor mistakes.

please hide you answers.

]]>http://www.mathisfunforum.com/profile.php?id=2053552016-06-09T21:29:25Zhttp://www.mathisfunforum.com/viewtopic.php?id=23124&action=new<![CDATA[Quickies #3 Assorted Math]]>That is always a tradeoff, a simple solution that you can code up quickly but may not be elegant or a smarter one that is, but takes more time to think of.]]>http://www.mathisfunforum.com/profile.php?id=337902016-06-08T13:45:22Zhttp://www.mathisfunforum.com/viewtopic.php?id=23116&action=new<![CDATA[Measure Theory]]>No, doing it the usual way is the way to go here. It is just an application of Fubini's Theorem behind the scenes.]]>http://www.mathisfunforum.com/profile.php?id=2060892016-06-06T06:39:27Zhttp://www.mathisfunforum.com/viewtopic.php?id=23094&action=new<![CDATA[Quickies #1 Math]]>]]>http://www.mathisfunforum.com/profile.php?id=2124862016-06-05T04:09:59Zhttp://www.mathisfunforum.com/viewtopic.php?id=23103&action=new<![CDATA[True or False easies]]>I am getting the same answer (:]]>http://www.mathisfunforum.com/profile.php?id=2120902016-06-02T06:58:15Zhttp://www.mathisfunforum.com/viewtopic.php?id=23098&action=new<![CDATA[Elliptic Curves]]>#10]]>http://www.mathisfunforum.com/profile.php?id=2060892016-06-01T08:21:31Zhttp://www.mathisfunforum.com/viewtopic.php?id=23096&action=new<![CDATA[Probability exercise]]>Hi;

]]>http://www.mathisfunforum.com/profile.php?id=337902016-06-01T02:33:19Zhttp://www.mathisfunforum.com/viewtopic.php?id=22725&action=new<![CDATA[Probability question I created]]>I have verified bobbym's result indirectly. I do not have exotic resources but with pen,paper and to a very less extent calculator I did the work. I estimated sample space of 2 numbers with same total and paired them on first 2 and next to places. the result is 1288 cases out of 14P4 give equality of sum of 1st two numbers to sum of 3rd and 4th numbers.This is 23/429. The remaining probabilty is equally divided between > and < conditions. So the required probability =(429-23)/429 X 1/2 =203/429.]]>http://www.mathisfunforum.com/profile.php?id=2124862016-05-31T05:05:46Zhttp://www.mathisfunforum.com/viewtopic.php?id=23095&action=new<![CDATA[Factorial!]]>