divide 2x^2/(2x^2+1) to acquire 1-(1/2x^2+1)
then: ∫ 1-(1/2x^2+1) dx = ∫dx - ∫(1/2x^2+1) dx, yay..an easier integration...!!
= x-∫(1/2x^2+1) dx, and we know that ∫1/(u^2+a^2) dx = 1/a arc tg u/a
thus: x- (arc tg x√2) or x(1-arc tg √2) + C
guys please CMIIW...
]]>∫2x^2/(2x^2+1) dx
thx for all your help
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