And thank you both for showing your methods.
]]>You are welcome and happy latexing.
]]>I latexed it up for you.
When you have time try this site
http://latex.codecogs.com/editor.php
perfect math every time!
]]>Sorry, Bobby, I don't imply that yours is not easy to understand
No problem. I am glad to see your solution. Also, anyone who can do that problem I do not characterize as a novice.
Have you tried Codecogs?
]]>Then we must calculate all the different ways by which we can arrange the birthdays of 6 people in these 2 months: Either 5 people have their birthday in the first month and 1 in the second, or 4 in the first and 2 in the second etc. Obviously we do not consider the case of 0/6 or 6/0. For the first case, we first get 1 out of 6 (for the first persons birthday) and then for the second persons it will be 5 out of 5, and so on.
Here is the calculation:
The total probability is the product of the first two (66 x 62) divided by the total number of all different ways by which 6 people can have their birthdays in 12 different months, that is, 12^6.
So we have
]]>Surely you recognize that?!
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