Well done for that result!
Bob
]]>Very good result.
]]>And Bob I thank you too for your help!
Sent in the lesson and got 20/20.:cool:
]]>15. What is the perimeter? - Answer: E
A 31
B 26
C 58
D 35
E 22
F 59
Correct.
16. What is the area? - Answer: A
A 28
B 65
C 79
D 13
E 10
F 19
Correct.
This rectangle just became the base of a regular prism, with a height of 6:
17. What is the lateral area? - Answer: F
A 119
B 873
C 256
D 349
E 332
F 132
Correct.
18. What is the total surface area? - Answer: D
A 119
B 873
C 256
D 188
E 332
F 132
Correct.
19. What is the volume? - Answer: E
A 651
B 327
C 395
D 221
E 168
F 342
Correct.
20. What is the area of the largest rectangular side? - Answer: D
A 65
B 32
C 36
D 42
E 16
F 34
Correct.
Well done.
Bob
]]>Firstly Q6-10 are all correct. Well done!
Q11 and Q12 and Q14 are also correct.
I'll look at the last section in a new post
Bob
]]>For 13) you indicate that you need some help.
You have:
h = 4
b = 6
l = 8
V = ( 4 x 6 x 8 ) / 2 = 96
Answer is E.
]]>15. What is the perimeter? - Answer: E
A 31
B 26
C 58
D 35
E 22
F 59
16. What is the area? - Answer: A
A 28
B 65
C 79
D 13
E 10
F 19
This rectangle just became the base of a regular prism, with a height of 6:
17. What is the lateral area? - Answer: F
A 119
B 873
C 256
D 349
E 332
F 132
18. What is the total surface area? - Answer: D
A 119
B 873
C 256
D 188
E 332
F 132
19. What is the volume? - Answer: E
A 651
B 327
C 395
D 221
E 168
F 342
20. What is the area of the largest rectangular side? - Answer: D
A 65
B 32
C 36
D 42
E 16
F 34
I have an isosceles triangle with a height of 4 and a base of 6:
11. What is the area? - Answer: C
A 19
B 35
C 12
D 16
E 22
F 54
This triangle just became the base of a regular prism, with a height of 8:
12. What is the lateral area? - Answer: D
A 105
B 28
C 35
D 128
E 56
F 12
13. What is the volume? **need help solving
A 95
B 54
C 32
D 23
E 96
F 10
14. What is the area of the largest rectangular side? - Answer: D
A 95
B 54
C 32
D 48
E 96
F 10
6. a rectangular base with a width of 4
A Lateral area: 120; Volume: 98
B Lateral area: 192; Volume: 76
C Lateral area: 240; Volume: 51
D Lateral area: 176; Volume: 33
E Lateral area: 288; Volume: 75
F Lateral area: 100; Volume: 64
Volume:
a = 6 x 4
a = 24
v = 1/3 x 24 x 8
v = 64
Lateral Area:
6 + 4 + 6 + 4 = 20
20 x .50 = 10
10 x 10 = 100
Answer: F
7. a square base
A Lateral area: 120; Volume: 96
B Lateral area: 90; Volume: 64
C Lateral area: 176; Volume: 144
D Lateral area: 192; Volume: 35
E Lateral area: 288; Volume: 288
F Lateral area: 240; Volume: 75
Volume:
a = 6 x 6
a = 36
v = 1/3 x 36 x 8
v = 96
Lateral Area:
6 + 6 + 6 + 6 = 24
24 x .50 = 12
12 x 10 = 120
Answer: A
8. a rectangular base with a width of 3
A Lateral area: 192; Volume: 144
B Lateral area: 90; Volume: 48
C Lateral area: 276; Volume: 64
D Lateral area: 176; Volume: 144
E Lateral area: 92; Volume: 96
F Lateral area: 62; Volume: 24
Volume:
a = 6 x 3
a = 18
v = 1/3 x 18 x 8
v = 48
Lateral Area:
3 + 6 + 3 + 6 = 18
18 x .50 = 9
9 x 10 = 90
Answer: B
9. a rectangular base with a width of 5
A Lateral area: 100; Volume: 48
B Lateral area: 240; Volume: 112
C Lateral area: 176; Volume: 96
D Lateral area: 110; Volume: 80
E Lateral area: 288; Volume: 144
F Lateral area: 90; Volume: 64
Volume:
a = 5 x 6
a = 30
v = 1/3 x 30 x 8
v = 80
Lateral Area:
6 + 5 + 6 + 5 = 22
22 x .50 = 11
11 x 10 = 110
Answer: D
10. a rectangular base with a width of 7
A Lateral area: 240; Volume: 64
B Lateral area: 188; Volume: 96
C Lateral area: 176; Volume: 144
D Lateral area: 130; Volume: 112
E Lateral area: 144; Volume: 215
F Lateral area: 100; Volume: 128
Volume:
a = 6 x 7
a = 42
v = 1/3 x 42 x 8
v = 112
Lateral Area:
7 + 6 + 7 + 6 = 26
26 x .50 = 13
13 x 10 = 130
Answer: D
]]>Glad you enjoyed our discussion about these problems. We have identified a big error with the work that Compu High are teaching you. The teaching page is available as a 'demo' so I have been able to read it all. The volume calculations are fully correct but the slant height section is WRONG.
Because I am a teacher of maths, I cannot just let you do these questions without showing you the correction. I'll do that first. Then you'll want to get their answers so you get full marks. That's OK. I have used their method and Q6 to Q10 all have a 'correct' answer. So hopefully, at the end, you will understand the work properly and be able to get full marks. I would just add, this is not the only criticism I have of this on-line course but I won't burden you with all my objections. Let's get on.
Correction: If you buy some wire so you can make a wire-frame version of these pyramids, you could proceed as follows. (see diagram)
(i) Cut two lengths a and two widths b. Join them to make the base rectangle.
(ii) Join the diagonals to find the middle and make a temporary wire for the height h. This fixes the vertex.
At this point the five points of the pyramid are all fixed.
(iii) You can cut four wires to join the base to the vertex and the model is complete.
It is not necessary is say how long the red lines for the slant heights are because they are already there, whatever size they need to be to join the midpoints of the base to the vertex. Just choosing a length for these red lines is not an option. Their lengths can be calculated using Pythagoras' theorem. Furthermore, with a rectangular base the two slant heights will not be the same, so giving a single slant height value is only possible where the base is a regular polygon. A rectangle is not a regular polygon.
This is why I have had such a problem with the slant height values given. The pyramids described cannot exist because those slant height values won't work!
Sorry for the rant, but I felt I had to get that off my chest. I feel better. If that's leaving you worried and confused I apologise, but I have to take account of the possibility that other members of the forum may be reading this thread and I don't want them being taught incorrectly.
So now, back to the problems. You can, of course, ignore all I have just said, and concentrate on getting the 'right' answers. (Anyway, once you have a volume, you'll know which answer to choose, without having to calculate the lateral areas at all. This is another criticism whoops, I'd better move on!)
The formula for the volume is
You have done Q6 volume correctly.
Their formula for lateral area is
So what you need to do is
(i) Add a + b + a + b to get the perimeter (distance around the base).
(ii) Calculate 1/2 of this and multiply by the slant height.
You can be fairly confident you have the right result if you can choose a single multi-choice answer that fits both the volume and area you have worked out.
Good luck.
Bob
]]>The shape is a pyramid with:
6. a rectangular base with a width of 4
A Lateral area: 120; Volume: 98
B Lateral area: 192; Volume: 76
C Lateral area: 240; Volume: 51
D Lateral area: 176; Volume: 33
E Lateral area: 288; Volume: 75
F Lateral area: 100; Volume: 64
So this is what I did. First I got the area of the rectangle:
a = 6 x 4
a = 24
v = 1/3 x 24 x 8
v = 64
That's what I'm getting for the volume.
As for the lateral area, would I have to do:
2 x 6 x 8
2 x 4 x 8
Get the answers for these, add them together to get the perimeter and then move on?
]]>Bob
]]>