When you differentiate back, do you get the same function? I do not.
]]>Hi;
Did you test that second answer?
Yeah.
]]>f:[0,3]->R f(x)=max{3-x,2x+[x]} . Show that f is integrable on[0,3] and calculated integral of f(x)
f is integrable because it is piecewise continuous (except at the right-hand end point), i.e. it is continuous over the subintervals [0, 1), [1, 2), and [2, 3). (It doesnt matter if its not continuous at an end point.)
]]>Did you test that second answer?
]]>The first can also be solved using x^4+x^2+1=(x^2-x+1)(x^2+x+1) without complex numbers.
For the second one, I am getting
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