Angles PQS and SQR are shown with two arcs. I think this can be interpreted as meaning that they are equal.

So in triangle PQS that angle can be found and then in triangle SQR you know two (and therefore all three) angles and a side. So x can be found.

Bob

]]>Solve for x

Now I can solve all the sides and angles on the top triangle but I can't find a way to solve anything else on the bottom trianlge.

I am guessing that we need to either get some congruent triangles or draw triangles in here to get the third piece of information thats missing from the bottom triangle. I just can't figure out where or how to start on that.

Any help would be appreciated

]]>