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#1 Re: Help Me ! » What is Mathematically wrong with my proof? » 2011-02-24 16:21:40
ahh yes sorry about that its supposed to say:
Proposition: For any integer n, the integer n is even if and only if n^2 is even.
Proof: Let n be an integer so that n^2 is even. By definition of even, we know that n^2 = 2k . Assume n = 2m and so we have that n^2 = (2m)^2 = 2^2 * m^2 = 2(2m^2) . Since m is an integer, then 2m^2 is an integer, since the integers are closed under multiplication. Note that n is even.
#2 Help Me ! » What is Mathematically wrong with my proof? » 2011-02-24 16:08:52
- ProofMaster23
- Replies: 4
I did this proof but my teacher says there are some mathematical problems? I have tried forever, any help?
Proposition: For any integer n, the integer n is even if and only if is even.
Proof: Let n be an integer so that n^2 is even. By definition of even, we know that n^2 = 2k . Assume n = 2m and so we have that n^2 = (2m)^2 = 2^2 * m^2 = 2(2m^2) . Since m is an integer, then 2m^2 is an integer, since the integers are closed under multiplication. Note that n is even.
Hope that makes sense. Thanks!
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