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#1 Help Me ! » Please confirm <circular function trigonometry) » 2008-03-27 02:41:20
- redXI
- Replies: 1
Solutions to 2 sin 2x = -3^1/2
First, I simplify the trigonometric equation:
sin 2x = (-3^1/2)/2 ---- 0<2x<720 degrees
...find the basic angle which is 60 degrees
Find the values of 2x between 0 and 4pi that satisfy that equation, this is the part where I get lost:
2x = 180+60, 36--60, 360+180+60, 360+360-60 degrees
x = 120, 150, 240, 330 degrees
Now, I only wonder how to input proper 180 and 360 degrees to get the X?? How come in some part the 60 degrees is positive and some negative? Thanks.
#2 Re: Help Me ! » How do I transpose equation? » 2008-02-27 01:05:39
I see now. That's easy.
#3 Help Me ! » How do I transpose equation? » 2008-02-27 00:25:14
- redXI
- Replies: 2
So I am studying graph and modelling now and I found this equation:
yx-3x+1=0
How do I make y as the subject? I need it to sketch the hyperbola graph.
Thanks.
#4 Re: Help Me ! » Quartic functions(Simple but confusing) » 2008-02-25 02:21:29
Awesome. I can do it now. Thanks.
#5 Help Me ! » Quartic functions(Simple but confusing) » 2008-02-24 23:36:54
- redXI
- Replies: 2
Hi everyone. So I was trying to study for the upcoming test and I stumbled on these two questions on my book that puzzled me. 
1. The function f(x)=x^4+ax^3-4x^2+bx+6 has x-intercepts (2,0) & (-3,0). Find the values of a & b.
2. The functions y= (a-2b)x^4-3x-2 & y=x^4-x^3+(a+5b)x^2-5x+7 both have an x-intercept of 1. Find the value of a & b.
I've tried solving it but I messed up in the process. I also have this parabola question from my previous test that I can't seem to answer perfectly:
The parabola has a turning point at (z,-8); it intersects the y-axis at y=10 and one of the x intercepts is x=5. Find the value of z and equation of parabola.
So, I really hope people are eager to help me solving my seemingly simple questions. I am a responsible student and I learn fast. Thanks! 
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