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#1 Re: Formulas » high school inequalities » 2017-06-15 04:24:58

bob bundy wrote:

hi chrislav

I suppose this comes from basic logic theory, or from (probability) trees.


Thanks bob,sorry for being so inquisitive  .

But, i wonder, if we do not know the basic laws of logic and how are they ivolved in a mathemetical proof how can we be sure for the correctness of that proof??

#2 Re: Formulas » high school inequalities » 2017-06-13 09:51:03

bob bundy wrote:

hi chrislav

That wasn't quite what I meant.  There are 4 cases:

case 1.  a > b AND b > c
case 2.  a > b AND b = c
case 3.  a = b AND b > c
case 4.  a = b AND b = c

If you are able to prove the required result for each of the above, then you're done.



But i would like to know,if possible, what ,mathematical rule dictates that there must be those 4 cases

#3 Re: Formulas » high school inequalities » 2017-06-12 09:41:15

bob bundy wrote:

hi chrislav

Thanks for the quick reply.  Yes, you can use LaTex.  Look here:

That thread goes on for a long time but you'll read enough in the first few posts to get started.

Definition : a>=b <=> a>b or a=b

I think that definition is the place to start.  If you consider separate cases, eg a>b AND b=c, you can show the required result for each case.

Hope that helps smile


O.K .Let us start:

using the definition

Which is equal to:

But if this is correct which is the rule in mathematics we use to get the above ??

#4 Re: Formulas » high school inequalities » 2017-06-11 20:27:53

bob bundy wrote:

hi chrislav

Welcome to the forum.

Some people, looking at these, might say 'isn't it obvious?'  So I'm guessing this is a proof from first principles analysis.  Tp start you need to look at the definition of >=

If you post this back I'll see if I can help.


Thanks Bob ,you are right.

So the axioms and the  definition needed for the above proofs are:


1) the trichotomy law for ">"

2) a>b and b>c => a>c

3) a>b => a+c>b+c

4) a>b and c>0 => ac>bc

Definition : a>=b <=> a>b or a=b

By the way isnt there any LaTex we can use??

#5 Formulas » high school inequalities » 2017-06-11 10:49:30

Replies: 10

Prove ;

1) a>=b and b>=c => a>=c

2) a>=b and b>=a => a=b

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