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If you move one of the diagonal out parallel to the original one using bob's picture (HD // AC, HD = AC, AH = DC, BD ⊥ DH ), so that the two diagonals and the extended long base form a right triangle, and the new extended base length is DC + AB, you may use Pythagorean to find sqr ( DC + AB) = sqr(diagonal 1) + sqr (diagonal 2). I did not know how to embed the imagine here.
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