You are not logged in.
Pages: 1
Hi,
I have a question that I got from my maths teacher that pretty much says this:
Find the equation of the line with the gradient 2/3 (two thirds), passing through (1 2/3, -6) (one and two-thirds minus six).
All I know is I am supposed to use the point-gradient formula, but how is it actually done? As there are fractions when I substitute the numbers accordingly, I end up with 3y + 15 = 2x.
I get the feeling I've got the wrong answer...can someone please explain how I've gone wrong, and provide an solutions with an explanation on how to do it properly?
Thank you.
Pages: 1