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how do you make this step i guess is my question? it looks like someone is doingsteps in their head here but not putting them in the solution and that's really frustrating because i can't do that so i don't understand how they did it. oh well...like my dad says...go on to the next question. : )
but i asked where did the second ratio came from...i know i'm being dense but i just don't see it...sorry...if you can't spend any more time on this don't worry...i'll ask her on monday. i guess there are substitutions happening but i can't see them.
Ok...here's the solution they give...
First they say to create 2 ratios for the times (that's what my teacher said to do too) and then they give these in the solution:
25/1 and ch/b:bh/c (how do you get the second one????)
Then they set the ratios equal to each and say to find the ratio b/c....
25/1 = (ch/b)/(bh/c)
25(bh/c)= ch/b
b/c = 1/5
That's all they have beside the info in the question.
Ok...so that's where my teacher found this question. I looked at the solution but I still don't get it. 25:1 is the ratio of their times. does that mean that bh/c and ch/b are equal to their times? How do you get that...those ratios? How did they simplify the equation in the solution to 1/5? I am so confused! Algebra is the devil!!
Hi...I can't figure this out. Can anyone send me to a site that explains this clearly or provide a solution with an explanation would even be better.
Boyd leaves home to visit Carlene, the race-car
driver. At the same time, Carlene leaves home to visit Boyd.
They each proceed at a steady rate along the same road. After
passing each other, Boyd takes 25 times as long to complete
the trip as Carlene. Find the ratio of their speeds.
Even though it's a ratio don't I still need one more piece of info? I have an idea of what to do but I can get it to work out. Thanks!
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