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That is brilliant, your expressions should give me insight into how I am working out my expressions, and they could be neater, this also helps me understand that apples and oranges basically cannot be simplified. I am working on a solution that involves rounding and ascertaining the complete simplification, but it I can't really claim it.
Thank you
Graham Cammock
Certiain variables are known before the problem which allow us to acertain the complete simplication after the problem, i.e.: after I have done the big expression, however, although I know that the answer can be a complete simplifaction of apples and oranges, it is kind of impossible to claim it as my answer.
I just found it intersting and wondered if anyone knew how to further simplify addition or subtraction of apples and oranges.
Another example of apples and oranges:
(2π/3) (61/19) = (38π 183)/57
In this small demonstration you can see how apples and oranges do not simplfiy, although in more complicated examples complete simplifcations can be ascertained after the problem, and given certain variables first.
Yes, thanks, that is the expression, I have tried several times to simplfy such problems, however, the result is always the same, it seems to be apples and oranges, or different exponents, however, I know that the problem does completely simplify.
Here is smaller example:
(π/17) (1/7) = (7π17)/119
You can see how such problems build up with apples and oranges, that is, addition or subtraction from pi, or addition or subtraction of different exponents.
Does anyone understand?
I have a repeating simplification problem that I cannot understand involving addition or subtraction of different exponents, that is, I cannot simplify the answer any further although I know that the answer can be completely simplified. Can anyone help?
I.E.:
(3518357487π + 2668642945/π) / (256191079 + 194318661/π2)
This is as far as I can simplify the problem; however, I know the answer can be completely simplified.
I.E.:
206π/15
The simplification is a 100 millionth out although this is not a problem.
Does anyone understand?
Thanks fellas, your comments really helped me understand the problem, it seems that this is bascially not a proper binomial.
If I have anymore problems I will be sure to ask.
Graham Cammock
Does anyone know anything about fraction binomials with X in the common numerator?
E.G.:
(X/(6/25)) × (X/(1/5)) + (X/(111/250)) = 2/3
A value can easily be ascertained for the numerator after the multiplication, but the numerator is not X squared or X.
I.E.:
((148/5125) / (6/125)) + ((148/5125) / (111/250)) = 2/3
A square root of this numerator works before the multiplication, but the numerator is not X.
I.E.:
((√148/5125) / (6/25)) × ((√148/5125) / (1/5)) + ((148/5125) / (111/250)) = 2/3
Factoring this fraction binomial seems very difficult or impossible.
Can anyone help?
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