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That's good but
Find all points on the y-axis
If you do a sketch you'll see there will be two points. Get the other by using the minus square root.
B
Ok.
Our two y-values are:
y = 2•sqrt{5} - 3
y = -2•sqrt{5} - 3
all points of the form (x, 3)
So write in set notation like this:
ie. Not just the originally given points but all in the line.
B
Bob,
I am not too familiar with set notation language.
Can you please interpret what this means in English?
I've been there,
I've faced those lonely trials,
I've been there, I'm familiar with the miles.
So, when you're walking through the valley
of the heartache once again,
you're only going where I've already been.
The Speers
(C) 1986
Let's sing a Jesus song,
washed in the blood and coming home.
I've been redeemed to Him I belong.
Let's sing a Jesus song.
The Speers
(C) 1986
harpazo1965 wrote:1.The Bible is 66 books long (if you include both the Old and New Testaments).
2. The Bible has been known to interpret itself.
3. Wrong interpretation of the Bible happens when people try to read the Scriptures like a college textbook or magazine.
4. The Bible is a Holy book about a Holy God.
5. More than 50 percent of Bible prophecy has been fulfilled proving that the Bible is the flawless Word of God.
ok; not sure what tis has to do with the math of pi?
Moving on.
Bob wrote:amnkb wrote:(4 - 0)^2 + (-3 - y) = 6^2
I think you need
Bob
i dropped the 'square' on the second parenthesis
thanks for catching that!
(4 - 0)^2 + (y + 3)^2 = 6^2
(4)^2 + (y + 3)^2 = 36
16 + (y + 3)^2 = 36
(y + 3)^2 = 36 - 16
(y + 3)^2 = 20
sqrt{(y + 3)^2} = sqrt{20}
y + 3 = 2•sqrt{5}
y = 2•sqrt{5} - 3
You say?
If you have the plot ready, you should notice these points are all in a straight line. generally y = mx + c will give you the equation. When the line is parallel with one of the axes, the equation is even simpler: either y = constant or x = constant. I'll leave you to decide which and what the constant is.
Bob
I noticed that the value of y is constant for each given point.
So, y = 3 is the line which is parallel to the x-axis.
Now, the points given are as follows:
(0, 3), (1, 3), (-2, 3), and (-4, 3)
The values of x = { 0, 1, -2, -4 }.
You say?
If you have the plot ready, you should notice these points are all in a straight line. generally y = mx + c will give you the equation. When the line is parallel with one of the axes, the equation is even simpler: either y = constant or x = constant. I'll leave you to decide which and what the constant is.
Bob
Ok. I will work on this problem later when back at the house.
harpazo1965 wrote:A. Plot the points (0, 3), (1, 3), (-2, 3), and (-4, 3).
B. Describe the set of all points of the form (x, 3), where x is a real number.
amnkb wrote:how does your book do similar examples?
like are you supposed o do set notation or maybe a line equation?harpazo1965 wrote:The textbook does not give examples for every problem.
Do you have a hint for me or not?my hint was to check the book to see if they showed what sort of sol'n they want
like i said, theres more than one way to answer this
they say 'set' so i guess use set not'n
{(x,y) in RxR | x in R, y = 3}
The textbook does not give a sample problem for this question.
(4 - 0)^2 + (-3 - y) = 6^2
I think you need
Bob
Thank you, Bob. I will work it out again.
harpazo1965 wrote:Find all points on the y-axis that are 6 units from the point (4, -3).
Any hints?
do distanceformula like they showed in the book
'on the y axis' means x=0 so points have x=0
you have D^2 = (4 - 0)^2 + (-3 - y) = 6^2
solve for y
(4 - 0)^2 + (-3 - y) = 6^2
(16) - 3 - y = 36
13 - y = 36
-y = 36 - 13
-y = 23
y = 23/-1
y = -23
You say?
harpazo1965 wrote:A. Plot the points (0, 3), (1, 3), (-2, 3), and (-4, 3).
B. Describe the set of all points of the form (x, 3), where x is a real number.
how does your book do similar examples?
like are you supposed o do set notation or maybe a line equation?
The textbook does not give examples for every problem.
Do you have a hint for me or not?
yes
Feels good to get the right answer.
harpazo1965 wrote:There is a difference between a blink, a twink and a wink.
My question is:
Mathematically speaking, how fast is the twinkling of an eye?
amnkb wrote:a 'moment' means about 90 secs
how are you defining 'twinkling of an eye'?
some [people] say its a blink
other s say its the time for light to pass thru the lens, reflect off the back and bounce back out
either way its loads shorter than a momentharpazo1965 wrote:I define TWINKLING OF AN EYE as a faster time than wink or blink.
ok thats two things that a twinkle is not but not what a twinkle is
harpazo1965 wrote:Now, back to mathematics.
sry i only mentioned 'preachers' because you were talking about religion stuff
ive edited that outback to math -- math runs on definitions
what is your precise definition of 'eye twinkle'?
i couldnt find a definition thru google so i'm asking you
thanx
Whatever speed a TWINKLE is, it will happen that fast. Those in Christ will be, as Paul said, CAUGHT UP to meet the Lord in the air. I think the twinkling of an eye cannot be measured by mathematics. The entire event that Paul talked about is a supernatural event performed by a supernatural being that we call God.
harpazo1965 wrote:Pi & the Bible
https://www.biblegematria.com/pi-and-the-bible.html
bible is a big book
if you try hard enough you can probably invent whatever meaning you want from it
article reads like maybe trying to hard
try this: https://www.purplemath.com/modules/bibleval.htm
no need for reading hebrew or inventing number puzzles from characters etc
1.The Bible is 66 books long (if you include both the Old and New
Testaments).
2. The Bible has been known to interpret itself.
3. Wrong interpretation of the Bible happens when people try to read the Scriptures like a college textbook or magazine.
4. The Bible is a Holy book about a Holy God.
5. More than 50 percent of Bible prophecy has been fulfilled proving that the Bible is the flawless Word of God.
Find all points on the y-axis that are 6 units from the point (4, -3).
Any hints?
Given A = (a, a) and B = (0, 0), find the distance between A and B.
Let me see.
d(A, B) = distance between points A and B.
d(A, B) = sqrt{(0 - a)^2 + (0 - a)^2}
d(A, B) = sqrt{(-a)^2 + (-a)^2}
d(A, B) = sqrt{a ^2 + a^2}
d(A, B) = sqrt{2a^2}
d(A, B) = a•sqrt{2}
You say?
A. Plot the points (0, 3), (1, 3), (-2, 3), and (-4, 3).
B. Describe the set of all points of the form (x, 3), where x is a real number.
NOTE:
I know how to plot points on the xy-plane.
My question concerns part B.
Any hints?
Ok. Thank you.
Yes, those equations will work. You can most easily eliminate B, hence get A, then work out B.
Check your answer fits the facts.
Bob
Ok. Sounds good. Thank you.
Thanks. I found out that my equations also lead to the right answer.
Yes, those equations will work.
Bob
Good morning, Bob.
I worked out my own system of equations and got
the same answers. Of course, this is ab easy word problem.
My problem concerns more involved longer applications.
Sometimes I manage to set up the correct equation(s) but
most of the time it's an up hill climb.
Cool. I worked out my own system of equations in terms of x and y and got the same answers.
Check
24 + 48 = 72
24 is half of 48
Cool.
Pi & the Bible
https://www.biblegematria.com/pi-and-the-bible.html
Andrew and Beatrice each have their own savings account. Beatrice’s account has $600 less than three times what Andrew’s account has. If Andrew had $300 more dollars, then he would have exactly half what is currently in Beatrice’s account. How much does Beatrice have?
Let me see.
This problem is more involved.
Let B = Beatrice
Let A = Andrew
B = 3A - 600
A + 300 = (1/2)(B)
Is this the correct system of equations to solve this problem?
You say?