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Hi, thickhead yours is the right solution. Thanks for helping me
But thickhead I couldn't get how did you simplified from equation (2) to equation(4) i.e.
ab=30/c and a+b=10-c
so c³-10c²+31c-30=0
In (2) first term ab is clear ;second and third terms have c common i.e.c(a+b)=c(10-c). i hope you can simplify further.
In my maths test there came this question:
a+b+c=10
a²+b²+c²=38
a³+b³+c³=160
Find the values of a,b and c.
Please tell me the answer with explanation.