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Hello:
@bobbym, it is amazing that you didn't get the right answer for 8. Your diagram shows you were working on the wrong hyperbola!
The red one is the right hypie.
The correct solution is not yet given so I'll put it down.
This solution uses the defining properties of both ellipse and hyperbola.
Hello thickhead:
That's wrong too. All the terms are integers so you can't get an irrational answer.
Mistake is when you did
1000*1001/2-1023=49977
your calculation got all squished together
1000 * 100 (1/2) -1023 = 49977
the right way
(1000 * 1001) / 2 - 1023 = 499,477
Hello thickhead:
therefore required sum is 1000*1001/2-1023=49977
That's how we solved that but you've got to calculate as accurate as you think. That answer (49977) just can't be right.
I wasn't able to find more than one ordered pair for number 6, x = -1 and y = 0. What did you find ?
If you can compute it, then you understand it. Can you compute it?
Table[FromContinuedFraction[ContinuedFraction[0.008012018027, k]], {k,2, 6}]
{1/124,1/125,5/624,11/1373,16/1997}
Hello:
@Bobby: solving the second question was easy enough but how did you do the first?
An apartment without a number on it? No way. The answer is 49.
@bobbym:
3) How did you get those 2 answers.The EF algorithms you gave me won't do 1 / 2.
Hello;
I'm not a member and I upload there all the time.
How about how I used the probability command with a conditional in the latter?
So what is it for 3? With replacement or not?
When you're in doubt do both.
bobbym, what do you think of the second answer?
Hello;
You aren't going to finish with that awful Colonel story?
Feels good to have everything ready cause you've already did it?
The front end in Mma is confusing. He needs to learn its capabilities.
You have your hands full m.
He should change his screen precision. Six digits are for children.
Shift - Enter line 3 again and again.
In an iterative root finding process, we start with some seed value and try to improve upon that answer with each iteration, i.e, everytime we touch that value. We do so until the solution is satisfactory to some level of accuracy.
It's better to say a guess.
Hello:
Formula for an arithmetic sequence nth term.
{30,28,26,24,22,20,18,16,14,12,10,8} are how the seats are put.