Math Is Fun Forum

  Discussion about math, puzzles, games and fun.   Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ • π ƒ -¹ ² ³ °

You are not logged in.

Pages: 1 2 3 4

#26 Re: Help Me ! » Trigonometric Prove » 2013-05-21 03:26:30

debjit625

I was bit busy with my studies so I didn't reply...
Yes ,bob it worked

Thanks again

#27 Re: Dark Discussions at Cafe Infinity » Which Graphic Card and Laptop » 2013-05-20 19:29:58

debjit625

Well after more search I found Nvidia 730M doesn't support four non gaming DirectX 11.1 features ,two of them are for 2D which I don't need in my 3D programming and other two seems to be not very useful for my 3D work.The plus point of nvidia is I get features like Optimus, PhysX, CUDA, 3D Vision, FXAA, TXAA, OpenCL, Direct Compute,and much more which could be explored in 3D programming...

So I am going for Nvidia ,I am not concluding AMD is bad but at this very moment the over all advantages is given by Nvidia

Thanks bobbym and Agnishom

#28 Re: Dark Discussions at Cafe Infinity » Which Graphic Card and Laptop » 2013-05-20 03:58:52

debjit625

I already saw that...

#29 Re: Dark Discussions at Cafe Infinity » Which Graphic Card and Laptop » 2013-05-19 23:35:41

debjit625

Thanks Agnishom and also thanks to bobbym for that information about CUDA

#30 Re: Dark Discussions at Cafe Infinity » Which Graphic Card and Laptop » 2013-05-19 23:31:32

debjit625

Thanks for the reply.

I think NVIDIA GeForce GT 730M score 2 points as its a bit better than AMD Radoen HD 8730M in performance and also it have drivers for linux which are better than ADM's drivers.

But I see AMD Radoen HD 8730M support full DirectX 11.1 in case of NVIDIA GeForce GT 730M it only support some features of DirectX 11.1,that's what making me thinking ,as for 3D development its better to have full DirectX 11.1,but again NVIDIA GeForce GT 730M have PhysX which is an another area I would like to explorer...

Any suggestions ....

#31 Dark Discussions at Cafe Infinity » Which Graphic Card and Laptop » 2013-05-19 20:32:35

debjit625
Replies: 13

Hi,
I am going to buy a laptop ,is Dell Inspiron any good ...

Two models are quite good for my needs Dell Inspiron 14R and Dell Inspiron 15R
what you guys think about it?

The two models differ in screen size and graphic cards ,the screen size doesn't matters much for me but the graphic card does,so I have two choices

1) NVIDIA GeForce GT730M  2GB VRAM
2) AMD Radoen HD 8730M 2GB VRAM

Both cards are almost similar,so I am confused what should I do...

Thanks

#32 Re: Help Me ! » Trigonometric Prove » 2013-05-14 18:09:21

debjit625

Sorry for the late reply...

Thanks Bob I will try it.

#33 Help Me ! » Trigonometric Prove » 2013-05-12 03:59:04

debjit625
Replies: 4

If

,prove that

I can't solve this part

Thanks

#34 Re: Help Me ! » Help with trigonometric prove » 2013-05-06 03:36:43

debjit625

Thanks Bob for the reply

#35 Help Me ! » Help with trigonometric prove » 2013-05-05 20:40:03

debjit625
Replies: 2

Well let me tell this first,I am not asking for any solution as I have them ,my problem is something different...

I can do trigonometric prove but only to a limit for example these kind of questions I have no problem


or

or

or more general types I have no problems ,but there are some I am having problems and I understand that, I am not understanding the process or steps  involved in solving them for example
Question 1


Question 2


I am not able to solve these kind problems ,what I need to know is what steps you guys take to solve these kind of problems,actually I feel them very complex. faint

In short I do not need the solution for question 1 and 2 I need to know how you guys solve these.

Another thing ,my book have very few of these questions so I can't even practice more if you  guys have any resource it would be great. up

Thanks

#36 Re: Help Me ! » Electrical Engineering » 2013-05-05 19:56:49

debjit625

@Mrwhy
I think the form factor is not 1,as its the case of a square wave,but in the image posted by the OP its not clear what is the time period of the pulse so we can't regard it as a square wave.

For a pulse wave form factor is


where,D is the duty cycle i.e.. the ratio of the time when the pulse is high and the full time period of the pulse.

Good Luck smile

#37 Re: Help Me ! » Electrical Engineering » 2013-05-05 04:58:40

debjit625

Well the image is not good enough to show any kind of electrical transient.But I guess its a pulse..
Any current which is not constant as in case of DC ,is reffer to as AC,even a pulse. In your image it looks like a DC transient.As AC is not constant they are measured differently than DC.In any circuit AC could be measured with Average,Peak-to-Peak,or RMS value.

Now the form factor is the ratio of RMS and Average value.

In your case I cant calculate as it needs more information about the wave,it needs the time period of the pulse.

Good Luck

#38 Re: Help Me ! » Want to be sure... » 2013-03-10 21:20:48

debjit625

Sorry I was in hurry its will be -n .I edited it on the first post too...

Here is the answer

The problem was it just got out of my mind about multiplicative inverse i.e..

Thanks

#39 Re: Help Me ! » Want to be sure... » 2013-03-10 21:19:10

debjit625

Ok I just got it

,my bad

Solved the problem

#40 Help Me ! » Want to be sure... » 2013-03-10 21:09:01

debjit625
Replies: 4

Find the sum of the following geometric series

I got an answer of

But the book gives an answer of

I think its a mistake ,it should be

Or am I wrong

Just want to be sure...

Thanks

#41 Re: Help Me ! » Quadratic Equation » 2013-03-01 21:35:36

debjit625

@scientia I am sorry too, for being so rude
And sorry to everybody I could be a bit more polite...

@Agnishom, yes brother

And about the question, yes I have understood it ,its asking for the condition i.e.. a relation between the roots and the coefficients for which the roots will be in m:n ratio.

#42 Re: Help Me ! » Quadratic Equation » 2013-02-28 19:03:44

debjit625

Is this the gratitude I get in return?

scientia ,if you can read English and understand it then look at post #4 ,I appreciated your work ,I thanked you...

Doing the sum is nothing its simple....

Maybe what you don't understand is not the question but the English language?

Yes, in general I speak English and understand it properly, but this question is not very much clear and I think bobbym also agreed with me on #7

My main question on post #1 was about clarification of the question elaborately ,I was not asking about the solution.

If somebody ask you --- What the question is asking for ? Find the roots of equation

.
And you just solve the equation ,that what you did in my case ,will not answer his/her question, you need to explain him/her what does the roots means in an quadratic equation.

You knew what I asked for... but you yourself don’t understand the question clearly, posting the solution doesn’t means you know about it, their are many books where  you will find this question and its solution.

Now the main thing, please please please please never ever try to help me again in future ,just stick with your bed and have good dreams...

#43 Re: Help Me ! » Quadratic Equation » 2013-02-28 04:56:16

debjit625

I had also never seen this kind of stuff earlier...

Well in the book its done like this...

Find the condition that the roots of the equation

are in the ratio

Solution :

Let   

    and   
    be the two roots of the equation     

Now,   

               ---Eq 1

and     

                            ---Eq 2

From Eq 1 we have ,         

or ,   

or ,   

                          --- By Eq2

or ,   

which is the required condition

#44 Re: Help Me ! » Quadratic Equation » 2013-02-28 04:19:15

debjit625

The values of the coefficients are in post #1

I have seen that...
I am just confused what the question is asking for...

In the book the process is a bit different but the required condition is given like scientia did

But still I am confused... I think I have to think about some more time...

Thanks

#45 Re: Help Me ! » Quadratic Equation » 2013-02-28 04:06:12

debjit625

Ok I think you guys didn't understood what I was asking for...
I want to know what the question is asking for ,what condition ?

As bobbym showed I think the question is asking about the values of the coefficients which will make the roots of the equation in m:n ratio.Am I right ? if I am not please help me to understand

Thanks bobbym and scientia

#46 Help Me ! » Quadratic Equation » 2013-02-27 05:34:22

debjit625
Replies: 15

Find the condition that the roots of the equation

are in the ratio

My problem is that I didnt understood this question i.e.. the language ,what condition its talking about... the two roots may be ma and na that will be in the ratio but what I have to show/do here.


Thanks:)

#47 Re: Help Me ! » Logarithm problem » 2013-02-10 23:54:16

debjit625

Well that solved the problem ,but still I have questions...
I understood that you used change base formula on LHS to change the base of
gif.latex?log_45=\frac{log_25}{log_24}=\frac{log_25}{2}

bob bundy wrote:

hi debjit625
so your expression (from post 8) becomes (all logs now in base 2):
(2log5)/2 + 1 = (2log5)/2 + log2
Bob

But what I didnt understood is that how you got it on RHS
gif.latex?2\frac{log_25}{2}

As per me its like this
gif.latex?log_{10}2(2log_45+1)%20=%201

gif.latex?2log_45%20+%201%20=%20log_210

gif.latex?2\frac{log_25}{2}%20+%201%20=%20log_2(2*5)

gif.latex?log_25%20+%201%20=%20log_22%20+%20log_25

Thanks everybody it seems I have to learn a lot ,off course from you guys...

#48 Re: Help Me ! » Logarithm problem » 2013-02-10 19:44:31

debjit625

I need the next step ...
I am not sure how to prove LHS is equal to 1,shouldn't we only work with LHS and prove/show it is 1?

Thanks

#49 Re: Help Me ! » Logarithm problem » 2013-02-10 18:29:38

debjit625

Sorry I cant understand...
dividing both the sides by "log (base 10) 2" will give us
gif.latex?2log_45+1%20=%20log_210
2log(base 4)5 + 1 = log (base 2) 10

Thanks

#50 Re: Help Me ! » Logarithm problem » 2013-02-10 04:50:55

debjit625

I am not sure how to do it ...still confused

Pages: 1 2 3 4

Board footer

Powered by FluxBB