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What would be the equation if the ellipse is not cutting any axis?
Ok so x is +/- 2*((22/3)^(1/2)).
How do we know that it crosses the x axis?
Is this the equation of an ellipse?
can you help me with the algebraic way?
Thanks bobby, but why does the first derivative method work here and not in the following sum? (7x-2)^(1/3)+(7x+5)^(1/3)=3.
How to solve this problem
3(x^2+y^2)+2xy=88.
Some solutions do the first derivative and then substitute back into the equation, but why?
Can we solve it purely by algebra?
Thanks for your response.
I think, equating 0^0 to anything is our construct, I think we should leave 0^0 as it is without equating it to anything that we understand today.
Thanks, so how do we go about discovering 0^0 if 0 is the 'absence of anything'. (We are not talking of limits here)
Thanks for all the responses, these are very insightful.
But
1. why would a 0^0 situation arise, that it would need to be answered.
2. 0 represents the 'lack of anything'. So 'lack of anything' times 'lack of anything' would be something or even a set or is this gibberish. That is why I wanted to know what is it to try to answer 0^0?
Is it right to ask .... What is 0^0?
Is it right to ask ... What is 0^0?
gibberish
This is really a interesting thought.
Zero is used to denote an absence (of anything, not a particular thing). To compare it to something i think is a fallacy. ...but i dont know how we explain this absence in a series as follows ...,-3,-2,-1,0,1,2,3,.. Vs ...3,2,1,0. Which i think is your question.
Is it that putting zeroes to the right of a number is a different zero as compared to the one represent in the above 2 series?
37.420472708971416659388291417068961418100050153982..
How is the above expansion more accurate, is it converging to a value?? Just more number of digits, does that mean it is more accurate?
37.4204727089714017054
:-)
slightly more accurate - more number of digits:
37.4204727089714017054
37.4204727089714...
Apologies for my ignorance, what is a generating function
How can i find the partition for a zumkeller number? Is there a theorem to help find the partition and sum of zumkeller numbers?
thanks Bob your approach really helped ... a good question.
Angle FBC' = Arccos ((sqrt6)/4) = 52.2 degrees (approximately)
Angle C'EA' = arccosine (4.5/sqrt21) = 10.9 degrees (approximately)
A'C' = sqrt7
CF = Sqrt(3)
CC' = 2 sqrt(3)
FC' = Sqrt(15)
BC' = 2 sqrt(6)
triangle BCD = equilateral traingle with each side 2 sqrt(3)
a highly contorted figure...
C'A = 2 sqrt7
C'E = Sqrt 21
CC' = 2 X Sqrt3
A'C = sqrt 19
A'D = sqrt 7
A'B = sqrt7
AE = 1
EC = 3
BE = DE = sqrt 3
Cos A'CA = 4 / (sqrt19)
Cos A'DA = 2 / (sqrt7)
Cos A'BA = 2 / (sqrt7)
On a separate note - in the question it is mentioned as a square prism, how is this a square prism? Any thoughts
Thank you, this simplifies the problem completely... though i still need to calculate the answer...Thanks
Wow this looks complex
Is this a complete question?
Country A and country B exchange rate is 1:6, a product C is cost 11 dollars of country B currency.
Country A economy is in inflation, more than 10% of the money were issue, meanwhile social productivity increased by 20%, How many product C can be sold out by using 20 dollars of country A currency?