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#26 Re: Help Me ! » how to solve this? » 2016-01-15 00:18:23

What would be the equation if the ellipse is not cutting any axis?

#27 Re: Help Me ! » how to solve this? » 2016-01-14 15:42:10

Ok so x is +/- 2*((22/3)^(1/2)).
How do we know that it crosses the x axis?
Is this the equation of an ellipse?

#28 Re: Help Me ! » how to solve this? » 2016-01-14 02:27:52

can you help me with the algebraic way?

#29 Re: Help Me ! » how to solve this? » 2016-01-13 14:59:49

Thanks bobby, but why does the first derivative method work here and not in the following sum? (7x-2)^(1/3)+(7x+5)^(1/3)=3.

#30 Help Me ! » how to solve this? » 2016-01-13 06:31:21

NakulG
Replies: 15

How to solve this problem

3(x^2+y^2)+2xy=88.
Some solutions do the first derivative and then substitute back into the equation,  but why?
Can we solve it purely by algebra?

#31 Re: Exercises » What is 0^0 » 2015-12-31 19:38:11

Thanks for your response.
I think, equating 0^0 to anything is our construct, I think we should leave 0^0 as it is without equating it to anything that we understand today.

#32 Re: Exercises » Brittle Math #3 » 2015-12-31 03:01:35

Thanks, so how do we go about discovering 0^0 if 0 is the 'absence of anything'. (We are not talking of limits here)

#33 Re: Exercises » What is 0^0 » 2015-12-31 02:42:19

Thanks for all the responses, these are very insightful.
But
1. why would a 0^0 situation arise, that it would need to be answered.
2. 0 represents the 'lack of anything'. So 'lack of anything' times 'lack of anything' would be something or even a set or is this gibberish. That is why I wanted to know what is it to try to answer 0^0?

#34 Exercises » What is 0^0 » 2015-12-30 16:07:45

NakulG
Replies: 16

Is it right to ask .... What is 0^0?

#35 Re: Exercises » Brittle Math #3 » 2015-12-30 16:05:09

Is it right to ask ... What is 0^0?

#37 Re: Exercises » Found New n Interesting thing about Geometric Points » 2015-11-20 04:24:55

This is really a interesting thought.
Zero is used to denote an absence (of anything, not a particular thing). To compare it to something i think is a fallacy. ...but i dont know how we explain this absence in a series as follows ...,-3,-2,-1,0,1,2,3,.. Vs ...3,2,1,0. Which i think is your question.
Is it that putting zeroes to the right of a number is a different zero as compared to the one represent in the above 2 series?

#38 Re: Exercises » Get the area: » 2015-11-20 04:12:58

37.420472708971416659388291417068961418100050153982..
How is the above expansion more accurate, is it converging to a value?? Just more number of digits, does that mean it is more accurate?
37.4204727089714017054
:-)

#39 Re: Exercises » Get the area: » 2015-11-17 06:04:16

slightly more accurate - more number of digits:
37.4204727089714017054

#41 Re: Help Me ! » How can i find the partition for a zumkeller number? » 2015-04-03 01:35:45

Apologies for my ignorance, what is a generating function

#42 Help Me ! » How can i find the partition for a zumkeller number? » 2015-04-01 04:41:30

NakulG
Replies: 4

How can i find the partition for a zumkeller number? Is there a theorem to help find the partition and sum of zumkeller numbers?

#43 Re: Help Me ! » What is the Solution?? » 2015-03-07 11:12:46

thanks Bob your approach really helped ... a good question.

#44 Re: Help Me ! » What is the Solution?? » 2015-03-07 11:08:24

Angle FBC' = Arccos ((sqrt6)/4) = 52.2 degrees (approximately)

#45 Re: Help Me ! » What is the Solution?? » 2015-03-07 10:22:14

Angle C'EA' = arccosine (4.5/sqrt21) = 10.9 degrees (approximately)

#46 Re: Help Me ! » What is the Solution?? » 2015-03-07 10:00:46

A'C' = sqrt7
CF = Sqrt(3)
CC' = 2 sqrt(3)
FC' = Sqrt(15)
BC' = 2 sqrt(6)
triangle BCD = equilateral traingle with each side 2 sqrt(3)

a highly contorted figure...

#47 Re: Help Me ! » What is the Solution?? » 2015-03-07 09:58:09

C'A = 2 sqrt7
C'E = Sqrt 21
CC' = 2 X Sqrt3

#48 Re: Help Me ! » What is the Solution?? » 2015-03-07 09:21:00

A'C = sqrt 19
A'D = sqrt 7
A'B = sqrt7
AE = 1
EC = 3
BE = DE = sqrt 3
Cos A'CA = 4 / (sqrt19)
Cos A'DA = 2 / (sqrt7)
Cos A'BA = 2 / (sqrt7)

On a separate note - in the question it is mentioned as a square prism, how is this a square prism? Any thoughts

#49 Re: Help Me ! » What is the Solution?? » 2015-03-07 08:51:05

Thank you, this simplifies the problem completely... though i still need to calculate the answer...Thanks

#50 Help Me ! » What is the Solution?? » 2015-03-01 04:02:52

NakulG
Replies: 8

Wow this looks complex
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Is this a complete question?
Country A and country B exchange rate is 1:6, a product C is cost 11 dollars of country B currency.
Country A economy is in inflation, more than 10% of the money were issue, meanwhile social productivity increased by 20%, How many product C can be sold out by using 20 dollars of country A currency?

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