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Hmmm. I couldn't see the post on the other forum and I'm not about to join the forum.
A Friend is a wonderful person in your life that cannot be considered family or extended family in anyway.
A blind person never sees his friends, and likewise I do not see my internet friends, unless they post a youtube vid of themselves doing math. So the definition of friend could certainly be broadened to include virtual friends too, but the virtualness prefix will always be there since we are communicating through a sort of filter. Also todays telephones have poor digital quality one may notice. In fact as I recall, they had better quality to talk with your friends back in the late 70's and early 80's before the digital sampling was reduced to a mere kiloHertz for voice or something. It's rediculous. I can whistle songs to people over the phone so high, they can only hear a rustling of noise on the other end. It is dispicable really. But still friends are best maintained through actually meeting in real life and going skiing together or shopping togehter, or dancing together or talking over the loud band playing!!
Oh well, at least you are doing a fine job at manually addressing each instance as needed. Good Work.
Maybe you could block his email address, if he posts it, and change everything else to math math math Rover, math, math, math.
I saw a great poster in veterinarians office of a master talking to his dog and the dog heard blah, blah, blah, blah, and then his name, and then blah, blah, blah... It was funny, and also they have a great periodic table of the vegetables at the vets too.
I see. I thought you sign up as a member an novice comes first, so he must'nt have posted more than 10 posts?
I heard last week they are still voting on the PIPA 964? bill tommorow the 24th. Not sure though.
I didn't notice, was it a guest or a username?
Oh, well it was a hard code to break, and maybe was just cobbledy-gook anyway.
oh, I see. I had just formed a theory that the second word after the second comma in the second sentence was either "tools", "books", or "enough" in French, when my post said it lost its connection or something when I submitted it.
Oh, thanks for that, Schildt, interesting name. I was working on a code in Help Me and someone deleted the post just because it had an email address in it. Couldn't the moderator just delete the email address and leave the code I was working on.?
So, looking at all the posts so far, we see early on that there are either 4 and 0 shown or 3 and 1 shown or 2 and 2 shown to you by looking at the two other gals.
If 4 and 0 is shown, you know what you have. (what you've got).
If 3 and 1 are shown to you, then the missing 1 could be on you or in the pocket.
If the 1 is on you then the second person will see bicolors on you and doubles or bicolors on the 3rd guy.
The third guy will see what the second guy didn't see (backwards).
However, if 2 and 2 are shown to you, then you could have either alll red or all black or both.
The second person would see either 2 and 2 or 3 and 1 or 4 and 0, so this is very hard.
I have no idea what each person would guess and I give up for now.
A = H = L --> any of 3 possibilities on your forehead
B = G = K --> any of 3 possibilities on your forehead
C = E ----> either KR or RR on your forehead
D = I ----> either KR or KK on your forehead
F ----> you absolutely have RR on your forehead
J -----> you absolutely have KK on your forehead
Those are the 12 thingy-do's
Next we'll letter the 12 combinations you might see AND what MIGHT be on your forehead, maybe:
A.) KR KR => KR
B.) KK RR => KR
C.) KR KK => KR
D.) KR RR => KR
E.) KK KR => RR
F.) KK KK => RR
G.) KK RR => RR
H.) KR KR => RR
I.) RR KR => KK
J.) RR RR => KK
K.) RR KK => KK
L.) KR KR => KK
Now we must find the ambiguous ones and true ones looking for duplicates on left sides of equations.
Next we'll look at some possibilities.
Pretend you have KR on your forehead, list what you see on the others 2 gals foreheads?
KR KR
KK RR
KR KK
KR RR
Now pretent you have RR on your forehead, list what you see on the other 2 gals foreheads?
KK KR
KK KK
KK RR
KR KR
Now convert the latter list for RR on your forehead to KK on your forehead with substitutional logic.
RR RK
RR RR
RR KK
RK RK
Next we should break caseKR into the 3 forehead (front=[francais for forehead]) combinations:
caseKR1: KR KR KR
caseKR2: KK KR RR
Next we should break caseRR into the 3 foreheads:
caseRR1: RR KK KK
caseRR2: KR KR KK
Next we should break caseKK up just like caseRR's symbiotic relationship:
caseKK1: KK RR RR
caseKK2: KR KR RR
Let's start the thinking off at least.
K=blacK R=Red (K is an industry standard for black, since B is blue)
caseKK: Hidden: KK Exposed: KKRRRR
caseRR: Hidden: RR Exposed: RRKKKK
caseKR: Hidden: KR Exposed: KRKRKRI think the C authors were named Kernigan and Ritchie, if my 17 year memory subsists.
Yep, wiki says DoD used it and Ada is named after aleged 1st programmer from 1800's!!
Hey, you know the two guys that invented C?
They wrote a cool small book with a tremendous last chapter with the syntax of C very well defined.
I read it over and over long ago.
lots of parallel lines with those four circles.
Looks complicated.
Did you need to solve it?
Is ADA functional?
2**16 = 65536 and this # mod(101) = 88
See loop from post #2
It's straight from my $3.00 book!! Power residues for prime #101
See data loop:
1 Begin 2
4
8
16
32
64
27 54
7 14
28
56
11 22
44
88
This 88 is the answer. Note it is the 16th one in the list if 2 is 2**1, then 88 is 2**16.
with the 101 divmod.
mmmm... wiki article shewd a bit of it. Looks (dur) hard.