Math Is Fun Forum

Ok I was having problem with  Latex.... and yes thats write.

1/log(base a)b = log(base b)a ,is that what you wanted to know

Thanks

Thanks everybody...

Thanks bobbym for the link http://www.themathpage.com/aprecalc/factorial.htm
as I was searching factorial problems involving variables and it had some great stuff.

Now I got it thanks guys, it was so simple ,my book didnt have enough of factorials its more about permutation can you guys give me some resource on factorials...

Thanks

Read this
http://www.mathsisfun.com/algebra/quadr … ation.html

Good Luck

@ bob bundy
Ok I did all the problems,but I have some question regrding post #9 where you posted about question 2.

Well how can  x = 0 makes the expression goes to +/- infinity as dividing anything by 0 is undefined,and x is the denominator.

What solution set did you got for question 2 , 3 and 4?

Thanks

Well a program should behave what its programmed for. If it's programmed to use  Newton's method, it will  and its the same what you do on paper. But at the same time computers have limitations. In this case the limitation is on decimal points ,computers work only with binary numbers they don't understand decimal points they don’t even understand negative numbers
in binary we can only have positive whole numbers {0,1,2,...} and even whole numbers are limited ,the range will depend on the bits you are using to describe the number.

So how come we can calculate decimal and negative stuff on our computers?
Computers use a special format to represent decimal points, normally in the world of programming we say floating point numbers for decimal point numbers ex .. {0.25,0.55,...}.It is important to know that binary floating point system can only represent a finite number of floating point numbers in exact form, its because the number of bits used to represent the  floating point system, if you exceed that limit then you will loose the precision.

http://en.wikipedia.org/wiki/Floating_point

You have to need programming knowledge to understand these...

If you want to know more about this format search "Floating-Point " IEEE is the most commonly used format.

Here is an example floating point numbers and their precision on my 32bits computer programmed in a C++ compiler with ANSI/ISO C++ standards
float type data gives 6 digit precision.
double type data gives 10 digit precision.

Good Luck

Sorry still can't understand...

How can x be +/- 4 ,lets put it in the equation and see
Taking x as 4

Taking x as -4

So I think x can't be +/- 4

Yes I can understand that,but how you came upto "-3 <  x < 0" we just cant guess any range I want to know what are the steps,in your post #2 the case 1 is ok it gives 

but case 2 doesn't give any result expect than x is 0 and case 3 which you actually explained in post #5 gives

but as already given

. But thats not the answer and still where is

.

Thanks for the reply

Well still I am having problem to understand it...

How you can take the case (-∞,-3) as x can't be -4 or 4 ?

I did it a different way I just assumed two cases when x>= 0 and x<0
Here is what I am doing

So we can write

This far I did it... and I can also see that x can't be -3 or 3 as it will make the denominator 0.
But I can't find a proper steps to come to a proper solution set...I am still trying....

This point can't be from the equation

,let substitute the values of x and y in the equation

Ok ,I was going to ask to you to show the steps but suddenly I realized that I have got it...
Actually I answered my question in post #9

Thanks for your time bro, "talking to you made my crazy mind to work"