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#51 Re: Help Me ! » Why is this? » 2011-04-20 22:18:28

Yes, if y is f(x) or y(x) then its inverse would be x(y) or just x. The inverse has to be in terms of y so there is a y to solve for.

I am sorry to be confusing but that much, at least, is correct if not with clarity.

I see that canceling d can sometimes be a bad idea.


As I said, the inverse need be in terms of y so there is a y to solve for. I still do not get why solving for that y produces the function and not something else when we are starting with derivatives. I guess I will just keep looking at it.

#52 Re: Help Me ! » Why is this? » 2011-04-20 09:48:18

I am not a master of the theory behind calculus. Are differential operators a thing that can be canceled out the same way a variable may be canceled?

If we want to set the derivative of f equal to the reciprocal of the derivative of the inverse of f, we might write

where f-inverse is a function x in terms of y. That is,

Now I know that in differential equations one can move the dx over to the other side the equation when separating the variables. Does that mean that other operations can be used as well? Such as cancellation?

If we cross-multiple we can get

and if d is a thing that may be canceled out, we could then get

and, if so, since

we can reduce to


That may be a complete perversion of mathematics. Sorry, if so.

Does what I just did make sense? Is that one way of showing how the function y can be taken from the two derivatives without calculus?

Thanks so much for the help. smile

#53 Re: Help Me ! » Why is this? » 2011-04-19 12:41:33

Unless I am mistaken, which I may very well be, that seems to be a proof of how the derivative of the inverse will be a reciprocal of the derivative of the function.

But why is setting the derivative of the function equal to the derivative of the inverse of the function and solving for y going to result in the original function?

I don't get it.

#54 Help Me ! » Why is this? » 2011-04-18 08:39:08

Reuel
Replies: 8

Why does the derivative of f set equal to the reciprocal of its inverse return the original function when solved for f?

For example, consider a generic quadratic such as

the inverse of which is the quadratic formula (with y intact)

considering only the positive form of the solution.

If we differentiate f we get

and if we differentiate f's inverse, g(y) we get

If we set the derivative of f equal to the reciprocal of g, its inverse, we have

and if we solve this equality for y we get


which, of course, is our original function.



I showed this to my math teacher and he didn't really answer my question. I am curious as to why this is true. I know that the derivative of f will have reciprocal derivatives in the derivative of its own inverse, but why does setting the derivative of f equal to the reciprocal of its inverse result in the original function? Is there a proof or anything?

Thanks. smile

#55 Re: Help Me ! » Eigenvalues, Eigenvectors » 2011-04-18 08:25:39

Thanks, everyone, for your input.

#56 Re: Help Me ! » Eigenvalues, Eigenvectors » 2011-04-05 08:49:12

Here is a problem from a handout I tried.


I got


Is anyone getting similar answers? smile

P. S. Thanks for the help.

#57 Re: Help Me ! » Eigenvalues, Eigenvectors » 2011-04-05 08:36:46

Hmmm... do I need to remove the complex part?

#58 Re: Help Me ! » Eigenvalues, Eigenvectors » 2011-04-05 08:33:47

Here is my attempt at exercise 1 on page 3 of that pdf you sent. How does this look?




Which yields that λ is 1 ± i.

So that


And by the same logic it can be found that


If I am doing this correctly.

How does that look?


#59 Re: Help Me ! » Eigenvalues, Eigenvectors » 2011-04-05 08:15:36

Bob,

That is pretty great. I am going to try their exercises. Thanks for the link!

#60 Re: Help Me ! » Eigenvalues, Eigenvectors » 2011-04-05 06:57:03

The idea is to compute eigenvectors by substituting the eigenvalues in for λ one at a time. Then you enter the two into a general solution of the form

where L1 and L2 are the eigenvalues since the forum won't let me use λ in math text. V1 and V2 are the eigenvectors.

The initial problem, however, was not in finding a general solution but in recognizing how eigenvalues affect direction fields. It seems like such a nebulous business.

#61 Re: Help Me ! » Eigenvalues, Eigenvectors » 2011-04-05 06:38:25

Yeah. Then you subtract λ from both zeroes and find the determinant or whatever it is called. In many cases you will get what is called a characteristic polynomial which you solve to find one or two eigenvalues which may or may not be complex.

So in this case I guess we find that λ is ±4i.

#62 Re: Help Me ! » Eigenvalues, Eigenvectors » 2011-04-05 06:16:46

Some of these problems take forever and the concept of eigenvalues seems really vague. I was hoping someone had a list of clear-cut, straight-forward rules for how eigenvalues affect a system. I do not like it when math is sketchy. tongue

#64 Re: Help Me ! » Eigenvalues, Eigenvectors » 2011-04-05 06:00:17

Right now we are dealing with linear solutions. Supposing you have a linear system in terms of dy/dt and dx/dt you are asked to judge, just by the eigenvalues, how the system would act if plotted as a direction field.

For example, say you have the system


and you compute the eigenvalue to be -4, if I am even doing that part correctly (I don't know how to show my work with matricies on this forum) then you find the system, if plotted in Maple, rotates clockwise as a wheel would, rather than spiraling toward or away from the origin.

Here is an image from Maple to demonstrate my point (attached).

I am required to be able to tell, just from calculating the eigenvalues (and without Maple) what the system will do. Will it rotate? Will it go toward the center? away from the origin? Both?

Thanks. And I am good, thank you. How are you?



Edit: This won't let me upload my picture. Or I am unable to see my uploaded picture.

#65 Help Me ! » Eigenvalues, Eigenvectors » 2011-04-05 05:25:06

Reuel
Replies: 23

Hello.

I am an undergraduate differential equations student. My teacher and my textbook seem both incapable of saying in plain English how eigenvalues affect eigenvectors. Could someone who understands differential equations please help me to understand their nature?

How do positive eigenvalues affect a vector field? That is, does the vector field spiral sink, spiral source, rotate around the center?

How do negative eigenvalues affect a vector field?

How do complex eigenvalues affect it? Does it matter whether it is positive or negative real parts? How do such details affect the system?

I do not understand and I thank the helper who can explain it. smile

#66 Re: Help Me ! » Race cars - Differential Equation » 2011-03-09 07:48:47

I was going to try to find position functions for both of them but Leonardo is hard to do because of limiting information. I keep ending up with too many unknowns.

#67 Re: Help Me ! » Race cars - Differential Equation » 2011-03-09 07:45:18

Are you still working on this? Because I am completely stuck. I thought I had a good idea but... no.

#68 Re: Help Me ! » Race cars - Differential Equation » 2011-03-09 06:33:56

That could potentially pose as a problem. tongue


I see that.


Might all of this be best put into terms of position rather than velocity? Could that in some way be made to work with the positions of the cars?


In your's, where did

come from?

#69 Re: Help Me ! » Race cars - Differential Equation » 2011-03-09 06:24:10

I solved

to get

For time zero I simply set it equal to some number s so that C=s.

#70 Re: Help Me ! » Race cars - Differential Equation » 2011-03-09 06:19:18

I don't understand the answer either. Or how you arrived at it.

I am working on it, too, but with none much luck thus far.

#71 Re: Help Me ! » Race cars - Differential Equation » 2011-03-09 05:43:29

I am very thankful for the help. I guess I am having an off-week.

More information: The difference in velocity between Leo and Mike before Leo ran out of gas was 0 which means that as Mike continues along, he does so at Leo's original velocity as Leo decelerates. That Leonardo reached half his speed in half the distance to the finish line, it sounds as though he might completely stop on the finish line and the whole time he is working up to doing so, Michelangelo has been closing the 3-mile gap between them at Leonardo's original speed.

Hmmmmmm...

#72 Re: Help Me ! » Sailboat Drag » 2011-03-09 05:33:53

So I understand, you are saying that the fact I got the same answer as you is a coincidence?

I'll work it out your way and see what I get. smile

#73 Re: Help Me ! » Race cars - Differential Equation » 2011-03-09 05:28:04

Hey bobbym, haven't talked to you in a few weeks. smile

Well, we know that the relevancy of the problem begins when Leonardo is 2 miles from the finish line and, at that instantaneous moment, when his car runs out of gas, Michelangelo is 3 miles behind him, so the total span is 5 miles.

When Leonardo's car begins to slow its deceleration is proportional to the square of his remaining speed. Is this a good way of stating it mathematically?

Negative because he is decelerating?

We also know that after one mile (which is half the distance) his speed had also halved. Does that mean his deceleration is actually linear?

Thanks. smile

#74 Re: Help Me ! » Sailboat Drag » 2011-03-09 05:19:20

Hi gAr,

I believe so. I have this:


If I am understanding your question. smile

#75 Help Me ! » Race cars - Differential Equation » 2011-03-09 04:36:58

Reuel
Replies: 16

I am still trying to work through some of these word problems but this one has me stuck.

"Leonardo had been in the lead ahead of his rival race car driver Michelangelo for some amount of time by a constant 3 miles. Just 2 miles from the finish, however, Leonardo's gas tank ran empty and his car decelerated ever after at a rate proportional to the square of his remaining speed. Within another mile, Leonardo's speed had halved exactly. If Michelangelo's speed remained constant, who won?"


Should this be set up as two different equations, one for each driver? The lacking of numbers for speeds is confusing. I dunno, that snowplow problem came after a little effort and this one seems as if it should be a lot alike, but I could use a little help with this one.

Thanks ahead of time. smile

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