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## #1 2019-01-12 11:10:49

Member
Registered: 2013-01-22
Posts: 147

### Can someone help me write a proof for my idea?

I’ve got two ideas which if proven wrong will hopefully be a learning experience.

The first is a different way to do the Fermat Primality test.

And the second is that 2p^2 + 1 if it passes the Fermat Primality test and is not factorable by 3 will be prime.

Anyone interested? (I don’t know anything about Maths really, apart from GCSE and A-levels and my own research)

"Time not important. Only life important." - The Fifth Element 1997

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## #2 2019-01-13 11:30:08

Grantingriver
Member
Registered: 2016-02-01
Posts: 115

### Re: Can someone help me write a proof for my idea?

The second proposition can be proven or disproven as follows:

If we assume that p is a prime number then we would have:

but we know that p is a prime hence the last equation is impossible except for the prime number 3 and hence:

Therefore the only integer which is a prime and satisfies both the conditions, stated in the proposition, is the prime 3. However, if we assume that p is not prime we should exclude all of the integers which are not a multiple of 3 for the same argument stated above. So this will produce the following expression which satisfies the second condition of the proposition (that the number is not factorable by 3):

Testing the n values from 1 to 40 did not produce any pseudoprime that satisfies the second condition (the Fermat primality test). However, if a value of the latter expression at any given integer n turns out to be pseudoprime then it will provide a counterexample that disproves the proposition. On the other hand, if it is proven to have no pseudoprime up to a particular value of n then the previous argument constitutes a proof of the proposition for all integers below the value of the expression corresponding to the related value of n.

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## #3 2019-01-13 12:35:18

Member
Registered: 2013-01-22
Posts: 147

### Re: Can someone help me write a proof for my idea?

Thanks a lot Grantingriver! I think I understood all that you said. That’s great stuff.

I’ve actually posted on another forum where the idea’s been changed to:

If an integer, 2p + 1, where p is a prime number, is a divisor of the Mersenne number

, then 2p + 1 is a prime number.

My argument is that because divisors of the Mersenne number

can’t be < p if p is a prime number. Therefore if 2p +1 is a divisor of
it has no divisors as p is > the square root of 2p + 1. This will therefore make 2p + 1 a prime number.

What I’m also interested in is how to put the idea that:

An integer minus one, divided by 2, p times equals zero, will be a factor of

.
You may add the integer as necessary if minus one, divided by 2 results in an even number.

"Time not important. Only life important." - The Fifth Element 1997

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