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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 27,913

Hi,

.

Good attempt, Monox D. I-Fly!

CG#26. Find the equation of the straight line whose slope is -4 and passing through the point (1,2).

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 27,913

Hi,

CG#27. Find the equation of the straight line whose slope is

and passing through (5, -4).It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 27,913

Hi,

CG#28. Using the concept of slope, show that the following set of points are collinear: (2, 3), (3, -1), and (4, -5).

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 27,913

Hi,

CG#29. Using the concept of slope, show that the following set of points are collinear (4, 1), (-2, -3), and (-5, -5).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 27,913

Hi,

CG#30. Using the concept of slope, show that the following set of points are collinear (4, 4), (-2, 6), and (1, 5).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 27,913

Hi,

CG#31. Find the centroid of the triangle whose vertices are (1, 3), (2, 7), and (12, -16).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 27,913

Hi,

.

CG#32. Find the centroid of the triangle whose vertices are (3, -5), (-7, 4), and (10, -2).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 27,913

Hi,

CG#33. The center of a circle is at (-6, 4). If one end of a diameter of a circle is at the origin, find the other end.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 27,913

Hi,

CG#34.Using the section formula, show that the points A(1, 0), B(5, 3), C(2, 7), and D(-2, 4) are the vertices of a parallelogram taken in order.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 27,913

Hi,

CG#35. If the centroid of a triangle is at (1, 3) and two of its vertices are (-7, 6) and (8, 5), then find the third vertex of the triangle.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 27,913

Hi,

CG#35. Find the coordinates of the point which divides the line segment joining (3, 4) and (-6, 2)in the ratio 3 : 2 externally.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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