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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 29,567

Hi,

CG#85. Find the value of k for which the points (7, -2), (5, 1), and (3, k) are collinear.

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**Monox D. I-Fly****Member**- From: Indonesia
- Registered: 2015-12-02
- Posts: 2,000

Actually I never watch Star Wars and not interested in it anyway, but I choose a Yoda card as my avatar in honor of our great friend bobbym who has passed away.

May his adventurous soul rest in peace at heaven.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 29,567

Hi,

The solution CG#85 is correct. Excellent, Monox D. I-Fly!

CG#86. Find the value of k for which the points (8, 1), (k, -4), and (2, -5) are collinear.

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**Monox D. I-Fly****Member**- From: Indonesia
- Registered: 2015-12-02
- Posts: 2,000

Actually I never watch Star Wars and not interested in it anyway, but I choose a Yoda card as my avatar in honor of our great friend bobbym who has passed away.

May his adventurous soul rest in peace at heaven.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 29,567

Hi,

The solution CG#86 is correct. Excellent, Monox D. I-Fly!

CG#87. Find the distance between the points (0, 0) and (36, 15).

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**Monox D. I-Fly****Member**- From: Indonesia
- Registered: 2015-12-02
- Posts: 2,000

Actually I never watch Star Wars and not interested in it anyway, but I choose a Yoda card as my avatar in honor of our great friend bobbym who has passed away.

May his adventurous soul rest in peace at heaven.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 29,567

Hi,

The solution CG#87 is correct. Neat work, Monox D. I-Fly!

CG#88. Determine whether the points (1, 5), (2, 3), and (-2, -11)are collinear or not.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**Monox D. I-Fly****Member**- From: Indonesia
- Registered: 2015-12-02
- Posts: 2,000

May his adventurous soul rest in peace at heaven.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 29,567

Hi,

.

CG#89. Check whether (5, -2), (6, 4), and (7, -2) are the vertices of an isosceles triangle.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 29,567

Hi,

CG#90. Find the values of y for which the distance between the points P(2, -3) and Q(10, y) is 10 units.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 29,567

Hi,

CG#91. Find the area of a rhombus if its vertices are (3, 0), (4, 5), (-1, 4), and (-2, -1) taken in order. (Hint : Area of a rhombus = ½ x (product of its diagonals)).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 29,567

Hi,

CG#92. Find the coordinates of a point A, where AB is the diameter of a circle whose center is (2,-3) and B is (1,4).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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**666 bro****Member**- Registered: 2019-04-26
- Posts: 33

Hi

Solution of CG#92 is A(3, -10).

"An equation for me has no meaning, unless it expresses a thought of God"- Srinivasa ramanujan

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**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 29,567

Hi,

Excellent! The solution CG#92 is correct!

CG#93. Find the area of a triangle whose vertices are (-5, -1), (3, -5), and (5, 2).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

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