Hitting with the second throw means you win. Missing with it means you lose. The third throw doesn't matter either way.

Therefore, the probability is a nice round 40%.

]]>I'm throwing 3 balls at a target.

I win if I can hit 2 in a row.I must throw with my right hand first, then my left and finally my right again. (Note: Successive throws are independent events)

I estimate that my right hand throws hit the target 70% of the times, while my left hand hit for 40%.

That analysis is for the above question. Or at least I thought it was a question. I thought you were posing this question and then the one where you hit the first throw.

]]>MLR meaning a miss on the first and RL

(.3)(.4)(.7)

but I'm assuming I hit on the first throw.

Sorry for all these replies. I'm not really good with probability.

(.7)(.4)(.7) + (.7)(.4)(.3)

And:

MLR meaning a miss on the first and RL

(.3)(.4)(.7)

]]>Sorry for my poor typing. It should read as below. I have edited the top post. Funny because it is the sane principle it gets the same answer. Is this understandable to you?

(.7)(.4)(.7) + (.7)(.4)(.3) + (.3)(.4)(.7) = .364

]]>what is your thought process?

Thanks.]]>

This is how I enumerated it without using the tree.

(.7)(.4)(.7) + (.7)(.4)(.3) + (.3)(.4)(.7) = .364

In actuality it is the same thing.

]]>I must throw with my right hand first, then my left and finally my right again. (Note: Successive throws are independent events)

I estimate that my right hand throws hit the target 70% of the times, while my left hand hit for 40%.

I am getting 36.4% just by treeing it.

]]>Thanks in advance for answering my question.

I'm throwing 3 balls at a target.

I win if I can hit 2 in a row.

I must throw with my right hand first, then my left and finally my right again. (Note: Successive throws are independent events)

I estimate that my right hand throws hit the target 70% of the times, while my left hand hit for 40%.

If I hit the target with my first throw, what is the probability that I will win? (Basically hitting on the next throw)

]]>