Welcome to the forum. I believe you're missing out a factor of 10 in your multiplication -- note that:

This might help:

I'm getting 20 as the correct answer when I run through your calculation in A. Let us know if you need any more help!

]]>No matter how I do this, problem (A) is supposed to resolve to 20A. I get 200A using the equation given in (A)

The textbook equation is give in (A) without any changes. So I ask, what am I doing wrong in my evaluation of the formula? Is it possible that the formula is incorrect or the answer given is incorrect?

]]>I'm confused in trying to compare your two methods.

In B

(200*1.0e-6)

What does this mean?

1.0 x e^-6 is a different thing altogether. e raised to the power -6 would not be a simple power of ten.

Are you using the 'exp' key on a calculator here. That would make this 1.0 x 10^-6 which makes this the same as A.

Also

0.02 (( 2 ) / 0.00002)

0.0002 * 1OOOOO

Here you have changed 0.02 into 0.0002. I cannot see why.

This physics is not my area but I can substitute values into a formula and evaluate. Please go back a step and say where the values have come from. Then I'll try to see what the correct evaluation is.

Bob

]]>(200*10-6) ((200*10-3)/2*10-6)

0.002 (( 2 ) / 0.00002)

0.002 * 1OOOOO

200V

B) VL = Δi /Δt

(200*1.0e-6) ((200*10-3)/2*10-6)

0.02 (( 2 ) / 0.00002)

0.0002 * 1OOOOO

20V

Where VL = Instant voltage on an inductor

Δi = Change in amperage

Δt – Change in time

The answer given in the textbook is “20 volts” However, using the book’s formula (A) I come up with 200V instead of the answer of 20V

So I created process “B” and I get the correct answer, but I cannot not explain why there is a difference between using the “Micro value (10-6) and using the exponent value 1.0e-6”