2022-12-10T03:16:58ZFluxBBhttps://www.mathisfunforum.com/viewtopic.php?id=28519i^2=-1 j^2=1 so k^2=0 e^kx=cosk x+ksink x e^kx=1+kx+0x/2+0k^2/6...=1+kx cosk x=1 sink x=x so tank x=x asink x=x Acosk x=1 acosk x=anything atank x=x e^ix is on the x^2+y^2=1 e^jx is on the x^2-y^2=1 so e^kx is on the x^2+0y^2=1 or x=+-1 e^ix x is half the area of a sector e^jx x is half the area of a hyperbola sector thingy then e^kx x is half the area of a triangle(does work with cosk and sink) conclusion:the zero factor crumples stuff up a lot]]>https://www.mathisfunforum.com/profile.php?id=2417972022-12-10T03:16:58Zhttps://www.mathisfunforum.com/viewtopic.php?pid=429486#p429486