I'm asking, because in school we use 9.8 for g.]]>

Where m[sub]1[/sub] and m[sub]2[/sub] are the masses of the 2 objects, and r is the distance between them.

And don't worry about going off-topic, the original question has been resolved so it doesn't matter too much.

]]>but... what's G? //sorry for the off-topic again ]]>

Then I used the g = Gm/r² thing to work out the mass of the earth, and then used that to work out at what distance from the centre the gravitional strength would be sqrt97. And then I just took that away from the standard radius to get the distance below sea level that it would have to be.

I didn't include all that in the post because it was off the point of the topic.

]]>If my calculations are right, then you'd need to be around 14km below sea level for gravity to be that high.

What are these calculations?

And the gravity at poles is different than the gravity at the Equatior.

http://www.mathsisfun.com/forum/viewtopic.php?pid=54379#p54379

]]>(5,4) - (-4,0) = (9,4) , sqrt( 9^2 + 4^2) = sqrt(97) = 9.85....

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