<![CDATA[Math Is Fun Forum / in my view it seems right]]> 2007-01-09T22:13:11Z FluxBB https://www.mathisfunforum.com/viewtopic.php?id=5667 <![CDATA[Re: in my view it seems right]]> I'm assuming there's a typo in your top line and that the 3 should be 3x. If so, then you have the right answer, but are using the wrong method.

To find the answer using the remainder theorem, you need to divide (4x³ + 2x² + 3x + 1) by (x+2). The remainder of that will be the value of the function at x=-2, which as you've already found, is -29.

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https://www.mathisfunforum.com/profile.php?id=641 2007-01-09T22:13:11Z https://www.mathisfunforum.com/viewtopic.php?pid=55702#p55702
<![CDATA[in my view it seems right]]> use the remainder theorem to evaluate 4x^3 + 2xx^2 + 3 + 1 , when x = -2

4(-2)^3 + 2(-2)^2 + 3(-2) + 1
-32 + 8 + (-6) + 1
-32 + 8 - 6 + 1
-24 - 6 + 1
-30 + 1
-29

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https://www.mathisfunforum.com/profile.php?id=5209 2007-01-09T20:32:31Z https://www.mathisfunforum.com/viewtopic.php?pid=55695#p55695