The post has been edited by Khushboo. She has replaced 14 by 21 in post#2. ]]>

oops i am sorry

Jane is correct

it should be=>x+2/3x=35

=>5x/3=35

or x=21and not 14

Thanxs

i see 21 there, not 14

]]>a)35 is (5/3) or 1 2/3 times of the number. Find 1 times the number.

b)the smaller number is 1/2(50-10). Just add 10 to that result and you have the greater number.

Jane is correct

it should be

=>x+2/3x=35

=>5x/3=35

or x=21

and not 14

Thanxs

]]>]]>Let the no. be x

=>x+2/3x=35

=>5x/3=35

or x=21

=>x+2/3x=35

=>5x/3=35

or x=21

b) let the no. be x,y

=> x+y=50......1)

=>x-y=10.........2)

you can simultaneously solve and cancel y

=> 2x=60

or x=30

similarly solve for y, cancel out x by putting minus sign beneath both the equations.

=>2y=40

or y=20

this should help

khushboo

]]>B)The sum of two numbers is 50 , their diffrence is 10 .Find the numbers.

thanks:)

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