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9pm to midnight is 3 hours (3 hr * 60 min/hr = 180 minutes)
midnight to 5:30 am is 5 1/2 hours (5.5 hr * 60 min/hr = 330 minutes)
total minutes: 510
510/5 = 102 minutes each
9:00 pm + 1 hr. 42 minutes = 10:42pm
& so forth
Since the exact number of poisoned barrels is unknown, ALL will have to be tested.
If you have 100 employees each take a sample, then the employer will automatically
be out 100 * 100 or 10,000 pounds.
It does not state what the additional cost of a dead worker might be. Just the cost
for doing the samples, whether poisoned or not poisoned.
This appears to be your method:
Simply, have ONLY ONE employee take a sample from each barrel in sequence.
Until, unfortunaltely, she gets the contaminated batch. There goes 100 big ones.
Get the next employee & start the procedure with the remaining barrels.
At the end, the employer will have found p (the number of poisoned barrels) and it
will have cost p * 100 each.
You will need to determine the probabilty distribution at each step.
I do not know if you understand the normal curve, or if you are just
missing the VBA stuff.
If you can state the procedure in simple language, then the
algorithm can be translated to VBA (or any programming language).
These are parts of a waypoint file.
A typical waypoint is given in Longitude/Latitude.
Some of the geocaching methods will give a distance & bearing to the next waypoint.
The file appears to be a listing of Degrees--minutes.
As listed a Long/Lat or Lat/Long pair will give a Lat of greater that 90 degrees,
so they are NOT geographic coordinates.
They are distance & angle waypoints.
EXCEPT the distances are not supplied.
You will need:
1) to get a GPS receiver,
2) find the initial starting point (from the clues from the geocache site)
3) physically get to that point
4) enter the DEGREES-MINUTES elements into your GPS receiver
& then look for the most significant object in that direction
you will probably, my guess, find a geocache at each terminus.
The distances are missing from this set of waypoints.
If you had the actual distances, you could plot a path
and skip the intermediates.
The information (from the source given) indicates a distance of approximately
30 miles.
If ( a big IF ) each leg of the way point is one mile,
then you would be about 31 miles from the starting point at the
end of the way point listing.
? 30-28,9-33,1-27,100-7,111-5,2-44,51-15,67-5,12-16,101-13,30-3,117-3,112-14,76-27,84-3,76-9,
22-15,75-4,51-12,99-36,101-14,100-2,10-13,92-5,60-12,6-2,34-4,103-10,3-45,49-5,90-4,18-11,
78-9,59-44,64-2,3-17,51-15,114-40,42-13
What exactly was the original phrase? How was the question asked and what is expected?
Are you sure that you typed in the correct data?
Could you give ALL of the information that you started with?
As stated it seems as if the total cost (same value) was not to be changed.
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The problem somewhat restated:
a value of 44.91 units (of APPLES) equal 59% of TOTAL COST
& a value of 23.40 units (of ORANGES) equal 41% of TOTAL COST
how much more value (UNIT PRICE) are the 23.40 units (ORANGES) compared to the 44.91 units (APPLES).
What is the difference of the unit prices between Apples & Oranges.
THEN, if 2.85 units (ORANGES) are added to the 23.40 units (AT THE same UNIT PRICE) to now total 26.25
units of ORANGES, What is the REVISED TOTAL COST?
what percentage of the REVISED TOTAL COST is APPLES and what per cent ORANGES?
---------------------------------
44.91 units (of apples) equal 59% of total cost
23.40 units (of oranges) equal 41% of total cost
Suppose the Total Cost is 100 euros.
1) the unit cost of apples is (59/44.91=) 1.31373859 euros each (for a total of 59 euros).
2) the unit cost of oranges is (41/23.4=) 1.75213675 euros each (for a total of 41 euros).
The oranges (per unit) are (1.75213675/1.31373859 = 1.3337 ) 33% more expensive than apples.
The 26.25 units of Oranges cost (1.75213675 * 26.25) 45.99359 euros.
The REVISED TOTAL COST is (45.99359 for oranges + 59 for apples) 104.99359 euros.
thus, the 44.91 units of apples represent (59/104.99359 = 0.5619390) 56.2% of TOTAL COST
and, the 26.25 units of oranges represent (45.99359/104.99359 = 0.4380609) 43.8% of TOTAL COST.
For any given ellipse, what is the maximum size circle (two required) than can be drawn inside the ellipse.
Thus, the circles must be centered on the x-axis and circles will touch the y-axis at the origin.
Two circles (touching) inside and ellipse -- What is the maximum radius possible?