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#1 Re: Help Me ! » probability » 2011-04-04 18:29:15

thank you very much. never would have solved it on my own.

#2 Re: Help Me ! » probability » 2011-04-04 12:45:17

ok so now have a new problem if you'll bare with me - what the probability of getting at least 3 positive results?

#3 Re: Help Me ! » probability » 2011-04-04 12:16:44

sorry to be a pest but that just isn't working out for me.

the fraction I get it 20/729. I'm assuming the first brackets is a fraction (which is where Imust be going wrong) and not something I vaguely remember from school. If so what is it so I can look it up.

But yes this appears to be the formula I want.

thanks for help


edit - ok yup I now remember matrices but still working on how that gets to a fraction

edot - figured it out - thanks very much

#4 Re: Help Me ! » probability » 2011-03-04 20:50:43

Thanks for that, but 2 things

1 just to make sure this is 3 positive results from 5 dice

2 its the formula I wanted as the example is just hypothetical.

cheers

#5 Re: Help Me ! » probability » 2011-03-04 08:45:16

thanks. You have five dice. both a 5 or a 6 gives a positive result. I want 3 positive results.

#6 Help Me ! » probability » 2011-03-03 23:30:41

danman111177
Replies: 10

what is the probability of geting a desired result from a number of attempts.

An example would be 3 x a result of 5 or 6 when you roll 5 dice. So you roll 5 dice and you want to get 3 results of 5 or 6.

Hope I made that clear.

Danny

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