Posts by NRG

NRG · Help Me !

gAr wrote:

Hi,
-------------------------------------------------------------------------
I don't remember the name of the rules!

Thanks!

The line is where I was getting stuck every time. I was not applying De Morgan's law here because I thought that since p(x) was preceded by ¬ I was not allowed!

Using what you've written I've finally understood that the law applies to single.. as well as boolean expressions such as ¬p(x)

Thanks again.

NRG

NRG · Help Me !

Hi,

Yes, that has been the first step I have taken in most of my attempts. (It seems like this is just trial and error..)

So I have this:

Step 1: re-writing ->

(And that's more or less where I come undone.)

Step 2: Extended De Morgan(i)

I think I'm negating wrong with that step, I don't know whether to negate the whole expression like I have, or to negate p(x) and (-qx or r(x) separately, or to negate each term separately.

I've tried all of those anyway..

NRG · Help Me !

Hi guys,

I'm trying to show this equivalence using boolean algebra, but I'm completely stumped. (I've spent about 20 hours and have got nowhere).

Any clues on where to start? I've tried rewriting -> as a first step as well as extended de morgan(i), but I've been at this for so long now I'm beginning to wonder whether de morgan was lying.

Regards

Math Is Fun Forum

#1 Re: Help Me ! » Boolean algebra. » 2011-03-25 04:19:28

#2 Re: Help Me ! » Boolean algebra. » 2011-03-25 00:44:33

#3 Help Me ! » Boolean algebra. » 2011-03-24 12:31:24

Board footer