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the initial diffrential equation is not Given.
i've to proove the above given Equation as the phase shift thru a thin lens .
i,hve edited the above equations ...
Steps involved in Solving the differential Equations.
d2 X/dx2-λ2X = 0.
&
d2 T/dt2-(λ2v2)T = 0.
steps involed in calculating this integral.
Bn= 2/L ∫ f(x) Sin(n.pi.x)/L dx.
f(X)= hX/Xo when O<X<=Xo.
=h(L-x)/(L-Xo) ,when Xo<=x<L
roots of the equation..
D²x-m²x=0 . it is a differential equation
how can we write the solutions in the form of (a+ib)
Ok ihve got the previous one ...
Can u help me out in calculating the Phase Shift through a thin lens of focal length f.
where d is the lens diameter. and h is the distance from the optical axis.
solution is like this.
P(h) = K/2f [ (d/2)² - h²].
Ok ihve got the previous one ...
Can u help me out in calculating the Phase Shift through a thin lens of focal length f.
where d is the lens diameter. and h is the distance from the optical axis.
solution is like this.
P(h) = K/2f [ (d/2)² - h²].
can u plz give me the steps involved in taking the solution of differential equation.
y= c1 exp(kx)+c2 exp(-kx) into the form y= c1 sinkx+ c2 coskx.
iam looking for the values of X.
sorry this is the equation i,ve got after solving matrix... so we canot take θ =Δ .
x2 -x(cosθ{exp(iΔ)+exp(-iΔ)})+1=0
Can you plz help me in finding the roots of this equation.
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