Math Is Fun Forum
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#1 Re: Introductions » About Me!! » 2007-04-13 10:21:57
so your name is java , then what is that code man ........
in other words , why is your username java codeman ..........
even i like the game proximity
Is it T-Rex or Tyrannosaurus Rex?
("java" is just short for javacodeman.)
#2 Re: Puzzles and Games » Spot the error » 2007-04-12 14:38:15
Okay. I'm new to the boards (so this may be older than dirt here and I wouldn't know it), but here's an easy one that might be good for some of the younger crowd (I'm sure most of you have seen it).
Theorem: 1 = 2
Proof:
Let A = B Then,
A² = AB
A² - B² = AB - B²
(A + B)(A - B) = B(A - B)
Divide both side by (A - B) gives
A + B = B
Since A = B
B + B = B
2B = B
2 = 1
edit: (You can use the commutative property of addition to switch 2 = 1 and 1 = 2 
)
#3 Re: Puzzles and Games » Spot the error » 2007-04-12 14:06:28
First, note that S is closed, since its complement R\S = (-∞, 0.9) U (0.99, 0.999) U ... is a union of open sets, and thus open
I'll take a stab that the error lies above. I'm not sure what a ball is (maybe you can expound), but S doesn't seem to be closed to me. If S were a finite set, then I think what you wrote above would work. But S is surely an infinite set (with a cardinality equal to the counting numbers). Each element of the set get's closer to 1, but never reaches it. You never address the numbers on the other side of the set, because that union would be [1, + ∞) .
.999999999999.......... is equal to one, but does your set contain this number?
That's all I've got folks.
java
#4 Re: Introductions » About Me!! » 2007-04-12 13:52:53
Welcome, javacodeman. Nice username and avatar!
Thanks!!:D
#5 Re: Maths Is Fun - Suggestions and Comments » Deep Grey is a sorry game » 2007-04-11 14:52:00
I just wanted to post my frustration at the game. After just math-nelly picking a number of boxes, I thought I figure out how to win:
Let the number of boxes remaining be "B"
if B modulo 3 is equal to 1, pick one box
if B modulo 3 is equal to 2, pick two boxes
if B modulo 3 is equal to 0, you'll lose (assuming that the other player follows the above two rules)Since the starting point is B = 18 (which is divisible by 3) and since deep grey knows how to play, you can never win.
java
Okay, I'll recant somewhat. After figuring out the method of winning, I assumed that the programmer made deep grey smart enough to win every time. Apparently he lapses every once in a while.
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#6 Re: Maths Is Fun - Suggestions and Comments » Deep Grey is a sorry game » 2007-04-11 14:44:31
I typed in w i l l y - n e l l y and it keeps putting it up as hairy-nelly. What gives?
java
#7 Maths Is Fun - Suggestions and Comments » Deep Grey is a sorry game » 2007-04-11 08:36:34
- javacodeman
- Replies: 16
I just wanted to post my frustration at the game. After just math-nelly picking a number of boxes, I thought I figure out how to win:
Let the number of boxes remaining be "B"
if B modulo 3 is equal to 1, pick one box
if B modulo 3 is equal to 2, pick two boxes
if B modulo 3 is equal to 0, you'll lose (assuming that the other player follows the above two rules)
Since the starting point is B = 18 (which is divisible by 3) and since deep grey knows how to play, you can never win.
java
#8 Re: Puzzles and Games » Spot the error » 2007-04-11 08:31:04
Great thread. I'm to post 51. I'm just replying so I can be sure to find it again later.
java
#9 Re: Introductions » About Me!! » 2007-04-11 07:27:51
Nice. What led you to pursue an MS in CS rather than mathematics?
That question has a multifaceted answer. I'll try to be brief.
* I had to take a CS class for my Math degree and really liked it.
* I took some graduate level math classes and didn't enjoy them nearly enough to keep pursuing that type of Math.
* An MS in CS is a very profitable degree in my line of work while an MS in Mathematics isn't.
java
#10 Re: Help Me ! » Creating an equation » 2007-04-11 02:44:49
I am trying to create an equation to use in a computer program. The aim is to find the value of Z, if the values of X and Y are known.
The Z value is going to be used to order some data, so the range does not matter.
I would like Z to increase as X and the result of the Y EQUATION increase.
The Y EQUATION needs to be able to be able to fit the following:
- When Y is between 30 and 40, the result of the Y EQUATION needs to be at its highest.
- When Y is at 1, the result of the Y EQUATION needs to be roughly a quater of its highest possible value.
- When Y is at 200, the result of the Y EQUATION needs to be roughly a quater of its highest possible value.
- No result of the Y EQUATION should be less than or equal to 0 when Y is greater than 0Any help would be a godsend.
Paul
I am assuming that you mean that "When X is between 30 and 40, Y needs to be at a its highest" and so forth?
#11 Introductions » About Me!! » 2007-04-11 02:39:17
- javacodeman
- Replies: 10
Hi javacodeman, and welcome to the forum! Feel free to start a thread about yourself in "Introductions"
Okay:
I stumbled onto this site while I was bored one day 
and looking for a good game of connect four. I stayed around (now I'm addicted to Proximity) and checked some of the puzzles and games out.
java
#12 Re: This is Cool » pi » 2007-04-10 04:54:30
I have a very Interesting Idea!
is it possible to convert pi to Computer code! represented by 1's and 0's
this may help to find a pattern!?
As already addressed, yes, it is possible to convert it into any number based system. The lower the number, however, the more digits are needed to carry the same amount of accuracy. So converting it up to hexadecimal would be a better idea than converting it down to binary.
java
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