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#251 Help Me ! » Asymptotes » 2009-03-07 21:18:01
- Identity
- Replies: 2
Find the asymptotes of the graph
usinga) Transformations
b) Solving
Thanks!
#252 Help Me ! » trig simplification » 2009-03-07 19:41:49
- Identity
- Replies: 2
A chute for unloading a transport plane has the side-view shown by
i) Find the equation for the inverse: [COMPLETED]
(I got
)ii) Engineers are modelling a new design for the chute: [UNCOMPLETED]
, where is found in i) above.Express the rule for this curve in the form:
, where r is a positive integer.I can't for the life of me see how I can simplify
! Help please#253 Re: Exercises » Question Bank : Age Group 14-15 : VIII » 2009-03-06 22:31:28
By
do you mean ?#254 Re: Help Me ! » List of quadrilateral vector proofs » 2009-02-28 01:48:48
Thanks,
So are all the conditions I posted correct and complete in their reasons?
#255 Re: Help Me ! » List of quadrilateral vector proofs » 2009-02-28 00:14:30
Thanks Kurre, that looks interesting 
#256 Re: Help Me ! » Help!!!!!!!! » 2009-02-27 22:29:00
7x6 = 6x7
7x8 = 8x7
If you know one of them then you know both of them! As for 8x8, you have to learn it!
#257 Help Me ! » List of quadrilateral vector proofs » 2009-02-27 22:26:45
- Identity
- Replies: 9
Can somebody please check my list of conditions for certain quadrilaterals or suggest some more possibilities? Please remember they must be applicable to vectors. Thanks!
To prove quadrilateral is a
Square:
Opposite sides congruent and all sides meet at right angles.
Opposite sides congruent and diagonals are perpendicular.
Diagonals are perpendicular and of the same length
Rhombus:
Diagonals are perpendicular
Opposite sides congruent
Rectangle:
All sides right angles
Parallelogram:
Opposite sides are congruent
Diagonal bisect each other.
Trapezium:
One pair of congruent sides
Cyclic Quadrilateral
Opposite angles are complementary.
#258 Re: Help Me ! » Continuity of cot(x) » 2009-02-24 19:44:47
Thankyou! 
#259 Re: Help Me ! » Continuity of cot(x) » 2009-02-23 23:32:38
I don't understand why that makes
invalid. Also I don't understand your argument from a 'shape' perspective. I am already familiar with the shape of the cotangent graph.#260 Help Me ! » Continuity of cot(x) » 2009-02-23 18:27:20
- Identity
- Replies: 7
Nobody seems to be able to answer this question, not even my math teacher.
Is cot(x) continuous at its intercepts?
Argument 1: Yes, because
Argument 2: No, because
, which is undefined.What is correct?
#261 Re: Dark Discussions at Cafe Infinity » Well done, ARR, Pe, Kate! » 2009-02-23 02:23:23
Kate Winslet had been nominated for 5 academy awards, I'm so glad she finally won
#262 Re: Dark Discussions at Cafe Infinity » Fires in Victoria » 2009-02-20 13:51:30
I don't mind that it's at Rod Laver Arena, what I mean is that they are protesting the mourning...
#263 Re: Dark Discussions at Cafe Infinity » Fires in Victoria » 2009-02-20 12:25:38
Westboro Baptist Church says they are going to picket the mourning ceremony at Rod Laver Arena. Gosh I hate those people so much 
#264 Help Me ! » Please explain solutions » 2009-02-15 21:44:56
- Identity
- Replies: 1
http://www.mathhelpforum.com/math-help/ … prove.html
I was looking for techniques to use to solve products of trig expressions so I found a problem on by tony123 which led me here to the above solutions
With Jane's solution, I don't understand what you do with the sextic equation in the end to find the product of the terms.
And with TPH's solution, I don't understand why you can assume the solutions are
and also whywhen previously it is stated that
thanks
#265 Re: Help Me ! » Log » 2009-02-10 16:38:22
if you venture into the complex realm, then you can define logarithms for negative bases:
How is this?
#266 Re: Help Me ! » Normal Distribution Problem? » 2009-02-04 23:39:20
Let X be the variable with E(X) = 52.3 and Sd(X) = 19.357. Let Y be the variable with E(Y) = 38.5 and Sd(Y) = 20.41
Then consider X-Y. Assuming X-Y follows a normal distribution, you can work out
and
Once you have both of them, solve
to find the probability that X is greater than Y.#267 Re: Help Me ! » Normal Distribution Problem? » 2009-02-03 19:04:28
I know but what do you want to do with the graphs? What does the question ask you to do?
#268 Re: Help Me ! » Simultaneous Equations » 2009-02-03 02:22:47
1) Substitute the value of y into the second equation:
Then substitute these values of x back into the second equation to solve for y.
2) Sub y into the first equation:
Then substitute these values of x back into the first equation to find the corresponding values of y.
#269 Re: Help Me ! » Normal Distribution Problem? » 2009-02-03 00:00:38
Sorry I don't understand what you want to do with your data?
#270 Re: Puzzles and Games » Metamorphosis » 2009-01-31 02:36:30
#10: STOP to MOVE
#271 Re: Dark Discussions at Cafe Infinity » How can you prepare for an IQ test? » 2009-01-29 13:49:20
Try the GAT, it's very similar to an IQ test (ok maybe not an IQ test, but definitely an aptitude test)
#272 Re: Puzzles and Games » which akatsuki member are you? » 2009-01-28 17:46:57
4) grim reaper is cool
#273 Re: Help Me ! » all about polygon » 2009-01-28 15:38:15
Maybe marivical means who found the construction (i don't know if it even exists though)
#274 Re: Puzzles and Games » Odd many out » 2009-01-28 10:30:40
Can we say Belgium is
#275 Re: Puzzles and Games » Odd many out » 2009-01-28 00:13:25
Italy is odd
nevermind didn't see previous post