You are not logged in.
Why would you want to expand that? Is it not already in simplest form?
I am as utterly perplexed as a porcupine pondering over an advanced calculus analysis problem.
Have a go, post your answer and how you got it:
This puzzle is taken from www.jtragon.co.nr
It, however, no longer exists on that site, as the site posts new puzzles frequently.
That's so sad. = (
I think I might get back to remembering pi, been very busy/lazy lately.
I wouldn't know much about this, but I think it may have to do with the sin and cos functions being periodic and hence the x point at -1 is virtually the same as the x point at 1.
Nevermind.
Yeah take it easy lightning how long do you spend on here each day?
LOL! Nice joke nice smilie
????
????
jeez you guys are smart!
qft... Also Jane must make a realllly good maths teacher...
Uuuagghhh... I have had lots of coffee since the start of the week and today my nose bled on 3 separate ocassions. =.=
Well... I'm sure he would stand a better chance than the average human at solving maths' biggest problems...
Funny thing is, even though he's Aussie, and the 'Mozart of Mathematics', go up to any average person on the street and 9/10 times they won't have a clue who he is.
How do you convert gradient into percentage rise? I forgot again. =.= Thanks.
Wow I never knew you could type symbols without latex
Quintuple Post!!! Lightning Is Dominating! The Sentinel Are Owning!
Thanks a bunch Dross!
For the interval AB, the coordinates of A and B are (x1,y1) and (x2,y2) respectively.
If M is a point on AB such that AM : MB = 3 : 1, find the coordinates of M.
As you can see from the graph, if Devante gets into a posting frenzy, he will post so fast that time will infact move backwards.
EDIT: Along with reading my terribly explained post, check this out - lots of cool, easy-to-understand info on this topic: http://www.mathsisfun.com/combinatorics … tions.html
Hmm, this has to do with the multiplication principle...
Lets do this team by team.
For the first teams, there are 3 possible outcomes: The home team wins, ties, or loses.
For the second teams, there are also 3, as well as 3 for the third, fourth etc.
You can try drawing a tree diagram. If you do this for all 8 teams, you should come up with the answer at the end of the tree - this is, however, exhaustive. If you had drawn the tree diagram, however, you may possibly have realised that for one team, there is 3 possibilites, for two teams there are 3^2 = 9, for three there are 3^3 = 27, for four there are 3^4 = 81, for five there are 3^5 = 243...etc
The possibilities are going up by powers of 3.
So at 8 teams, you would have 3×3×3×3×3×3×3×3 = 3^8 = 6561 possibilities.
In general - if event 1 has x outcomes and event 2 has y outcomes and both events are mutually exclusive, then the total possible outcomes is xy.
Let's try another example:
Lauren can spend her night a number of ways. She can see 1 of 5 movies, then go to 1 of 3 restaurants, then watch 1 of 2 movies on TV, then sleep in 1 of 8 positions.
The total possible outcomes from this would be
Event1 × Event2 × Event3 × Event 4
No.PossibleMovies × No.Possible restaurants × No.PossibleTVmovies × No.Possible sleep positions
5 × 3 × 2 × 8 = 240 different possibilities.
Just FYI, lightning's current PPD is a monstrous 33.
Cool, I'm looking forward to a limits page.
Are those really true stories though? I kind of find it hard to believe that a teacher or examiner would really appreciate a 2-3 word answer, no matter how meaningful it may be.
http://60minutes.yahoo.com/segment/44/brain_man
Amazing
This guy can remember pi to 22,514 decimal places, can calculate products like 31×31×31×31×31 in the blink of an eye, and if you give him any date, he'll tell you the day.
Not to mention he learnt Icelandic in a week.
I heard someone took philosophy, and on his final exam, got one question, and several pages of lines. The question was 'why?'.
Ugh. I do not want to do philosophy for my VCE!