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I cannot get it completely simplified yet. (without f^-1, that is).
That is not correct. That would not get the wanted integral. It would give:
Then, the coordinates of C should be (f^-1(pi/2), pi/2).
Is that the graph of f or f^-1?
Hi bobbym
The y-coordinate of C needs to be pi/2, though, not the x coordinate.
I'm sorry, but I do not see the patter. Could you explain a bit?
"One, two, three, one, two, three, drink."
Chandelier, Sia
Could you be more precise about what exactly you need to do?
But, multiplying by (-4) does not change the power of x there.
How did you get from:
hi Agnishom,
You are right to give this thread the title 'Consistency Hypothesis'. Is your theory consistent? Is your conjecture true ?
Consider this:
Universal set = {every situation that ever exists}
That includes this situation:
There exists "a situation in which there is no appropriate quote for that situation".
For if that situation doesn't exist then there is a situation that isn't in the Universal set =><=
Therefore your conjecture is false (sorry
) and your theory inconsistent.
Bob
ps. What is the IQ test story ?
How are so sure the situation you described exists?
These are exercises. You should hide your answers.
Hi Bob
I don't think f can take values between 0 and 1 either.
It's the number set we are the most familiar with. If we do not define it, we might as well not have mathematics.
Yeah, sorry.
13... Bb4
No, from d7 to e5.
12... Be5
11... QxQ+
10... pxp
9... e5
8... a6
7... Qe7
5... pxp
4... e6