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If they have words for genetic coding, then that would be mega long.
Is this guy a savant? I mean, is his brain configured differently? If he is then cool, if he isn't than woah!
I like the dog quivering it's tail in excitement, and generally those people who [are smiling]/[have books in their hands].
Wowoah! I got some crazy answer! It's probably wrong, but let me know if it isn't!
Let C be the midpoint of AB.
Hence,
Hence, the area is inside the curved part
The circumference of the cross section
So the total surface area is:
≈ 1364.43 = 1360 m² (3.s.f)
Identity wrote:There is no actual solution to this problem, but I'll show you what I would normally have done algebraically to solve it:
m ≈ -2.3829757691
But as I said, there is no solution. Substitute m into the LHS of the equation and you will not get m.
What is LHS?
And what would I'd have to say to show how it was solved?
It depends whether or not you've learnt about complex numbers.
We already have a chess game, right? Would it be too hard to expand it so it can be played multiplayer on Mathsisfun? The reasons you might have already guessed: it's fun and encourages logical development, especially for youngsters. ?
There is no actual solution to this problem, but I'll show you what I would normally have done algebraically to solve it:
m ≈ -2.3829757691
But as I said, there is no solution. Substitute m into the LHS of the equation and you will not get m.
What you do I think, is that you flick the 1st switch, then turn it off and flick the 2nd switch, leaving the 2nd switch on. Then, go upstairs and check on the lightbulb. If the lightbulb is on, then obviously the 2nd switch is correct. If the lightbulb is off, but still hot, then it is the first switch. If the lightbulb is off and cool, then it must be the 3rd switch.
If you are using a calculator, you should make sure you are working in radians, not degrees!
Use the formula
Hence
Thanks Jane, where did u get the formula from?
Hmmm, this is probably counter-intuitive because there is no such thing as a frictionless surface in our real world. Perhaps weird stuff just happens on those surfaces... why don't you try incorporating a little friction into the equation and see what happens.
Nice one Daniel! Never woulda thought of it myself
Everything in Post #12 looks correct
6. Durry vah tiff
7. Crow mus ohm
8. Ontra pra noir
9. Rawcuss
10. Dee rogue atorry
Hmm, apparently when it is divided by 2x it takes on a different shape. It is like a truncus, and when my calculator takes the limit of the whole thing it gets
I always have a tendency to understimate the value of abstracting what you see as geometry into algebraic equations. What I found interesting is that although you have 3 variables and 2 equations, you eventually come out with a numerical answer for x. Is that the case often?
Sorry it was wrong, I edited it so it is correct now
How can I work out the limit of this??
But it's always spring in Mathsisfun land!
If you were change the appearance of the front page to match seasons, you would only be right for about 1/4 of the world.
Hard... they're so similar, but I prefer the 2nd one, especially its simplification of the links on the left.
Is this kinda what you mean?
a = Chord length
b = Distance from Midpoint of chord to Centre
r = Radius
By Pythagoras:
Hence,
Hmm I just came up with an ill-advised hypothesis:
There is no clearly defined 'boundary' of the universe, that is to say, it is infinitely large. Therefore, couldn't it have been possible that the universe has been here all along, but just that all the stars and planets erupted from one explosive from a point in this forever-existing universe? The observations by Hubble just state that everything is moving away from each other. This doesn't mean that it is the universe is expanding, it might not have anything to do with that?
Geeze they always seem so mean
Since (x-1) and (ax^2 - bx + c) are both factors, simply divide
by to determine (ax^2 - bx + c) and hence a, b, and c.You should get
, hence a=1, b=-1, c=2.If you wait a sec, I'll draw up an image showing the division.
This was the final question on the test which we had on similarity and congruency. Baaah! It was worth 5 marks, and I couldn't do it, and the test was out of 30! I must say the questions on the test were much harder than I anticipated, but oh well, the harder the problems the more I learn I suppose!
Here 'tis (the diagram was not drawn on the paper):
thanks again