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Oh..oh I'm sorry.
Ok, don't worry, I wouldn't say anything, speak about your thoughts openly without any fear. I would not mind anything.
Why do you think Albert Einstein was a Fraud. He was one of the greatest scientist of all time(and my favourite also). And the discovery about the theory of general and special theory and theory of mass-energy equivalence(e=mc^2), was magic. He was a god on earth(according to me). You may not like physics but....plz dont call him a fraud.
Hi Ganesh,
Its an excellent article, which I discovered just after you posted the above message and it came in the top. Hi, I would suggest you to make this article "Sticky" here so that it gets locked in the top and any new member(and any old one too if they have not seen it) can come and see these interesting information.
You mean a stupid person?
Hmm, then I will compare myself with Albert Einstein.
hi Zeeshan 01
It is possible to show that all quadratics have a line of symmetry, and that for ones of the form y = ax^2 + bx + c this will be a verttical line.
If we start with the quadratic formula for the two roots:
it should be obvious that the two roots are symmetrically placed either side of the line
so the maximum will not be at
as you ask in post 31
Bob
Hmmm, but as far as I know, the max and min value of a quadratic polynomial is when the value of x is
. Check the link above.Hi;
Why is the equation of the circle different from what I got when I expanded (x – h)^2 + (y – k)^2 = r^2?
It is an equation of a circle at a point (h,k). If you want an circle at the origin [(0,0)] then h and k are both 0 and hence the equation is x^2-y^2=r^2.
But, the semi-circles and the circles may be of different sizes also. The size is not specifies in the question.
Why, isn't being above average a nice thing?
Ok I'll later, when I will get some time.
You can jot the value of -b/a instead of x in ax²+bx+c and can see it yourself.
Hi Zeeshan 01,
It is a great problem for us to solve problems if you use symbols like that so Plz Zeeshan, I would recommend you to either use the Unicode characters in the normal text or Latex, in here, which is mainly meant for writing mathematical expressions.
Hmm, you need to find the max. and min. value of a quadratic equation. The max value of a quadratic equation is as follows:
a>0-∞
a<0--D/4a
a>1-∞
a>2-∞What is this how you do this???
And question 1 ans is it is not a function!!!!!!
Sorry for the late reply but you may visit this site:https://brilliant.org/wiki/maximum-valu … -equation/
Hi Zeesan 01,
Log is nothing but the the power to which a fixed number (the base) must be raised to produce a given number.
If
, then . Now, . How? Just convertAnd for more information on logarithms visit http://www.mathsisfun.com/algebra/index-2.html
hi iamaditya
It was a joke. Mathematicians call numbers like Square Root (-1) imaginary numbers. There's a whole branch of mathematics devoted to the study, properties and applications of such numbers. Look here for a start:
http://www.mathsisfun.com/numbers/complex-numbers.html
They are called 'imaginary' because the imaginary number line is the image of the real number line. This choice has unfortunately led to some ignorant folk laughing at mathematicians for believing in something that is imaginary. When Isaac Asimov was ridiculed by one such critic, saying how can you have an imaginary number, he replied "Here's a piece of chalk; now hand me a half a piece of chalk." His point was that all numbers have no actual existence; they are all just abstract concepts. Take the number 3 for example. You cannot have a three; you cannot hold it; you cannot see it. All you see is the symbol we use to denote it. Out of context, it has no existence of its own. I have three children; but I have no three.
Thank you Phro for your jokes.
Bob
Hi Bob,
I know all about imaginary nos. but I did not get what you meant by Imaginary members. Hmm, now I understand what you meant.
I do not know, I do not see them.
You can not, since I haven't posted them only. I can do if you ask me to.
Oh, Thanks.
What do you mean by imaginary members???
Then would you say that ,I AM ABOVE AVERAGE?
Anyways, see post #97 2nd part. Can you do the 20 log problems??
Well, you say, AM I AVERAGE?
Well, bobbym if you are so intelligent then I think you could have easily done those difficult problems which I had submitted before here.
one of the reasons you say I can not live without the forum.
But what is the relation between loving your father and this MIFF???