Math Is Fun Forum

Hello there!

I found this place recently... looks really nice, I'm surprised I never found it before! I'm sure I'll enjoy it here

Edit: (thought I'd add a bit more than just "Hi there!")

I'm from Durham in the UK. I have to say, I'm impressed that this forum can use LaTeX inputs (and also that I can remember how to use LaTeX:P), otherwise things could get very messy! Am looking forward to helping a few people out and keeping up my math skills at various levels, I would hate to have them just fade away on me.

There's no particular area of maths that I would say I "specialise" in, or am more interested in than any other, though I can definitely appreciate the beauty of calculus for itself.

Alright, i'm trying to do this game with some friends..
And it's a timed game.. heres an example..
Start time is at 1: 20 pm
multiple people, have x amount of boxes to do
theres different amounts for each person.. and everyone starts at the same time but ends at a different time when they are done.
Lets say 1st player has 87 boxes, and finishes at 1: 43pm
How would i find out the amount of boxes done in hours ?
Is there a solution/formula base for finding out?
Any thoughts at all would help!

The only "viruses" that have been found for Apple's Tiger operating system require multiple installation steps, including the user entering an administrator's password.

That's because not enough people use macs to write viruses for it.

Virtually everything is more user friendly on the Mac.

Hence why I hate Mac's.  Too dang friendly, too many graphics.

Apple's operating system may not be free, but it certainly works better than Windows.

Yea, ok.  And by how do you judge such a comparison?  Your personal experience?

100% correct.  Remember, all you have to do is find the error in my proof.  You don't have to prove my conjecture incorrect, although you get 10 bonus points for doing so.  (1 goggol bonus points gets you a "Good job" from me).

To be a bit more exact, the error was here:

Let 2a = k.  k is defined as a natural number.  By forcing it to be equal to 2a, you are making k be even, and so the proof no longer applies to all even naturals.

Just a reminder All_Is_Number, you have up to 24 hours to post a new proof, or you may pass it on to someone else.

The Mythbusters proved that drunk driving is more dangerous than driving while talking on a mobile phone. Reead on for more information.

The Mythbusters set out on to a racetrack to prove that drunk driving is, in fact, more dangerous than talking on a mobile phone. They used three people - A female, a male, and another male. They were given ordinary cars, and they were all asked to perform three tasks - They were asked to try parallel parking, stopping at a certain sign, and going through an obstacle course. Of course, the Mythbusters tried each of these shortly after drinking a short amount of alcohol. They were asked no to eat anything for 2-3 days, for the maximum result. The drunk driving was terrible - Everyone failed the parallel parking and stopping at the sign, and one of them even failed all three tasks! They then tried the same with a mobile phone. They proved that it was easier driving with a mobile phone because of two reasons - One, they had better control while driving, and two, they could easily put the mobile phone down if they were to crash or have an accident.

Thus, the Mythbusters proved that drunk driving is more dangerous by a wide margin than driving while talking on a mobile phone.

The captain will take 98 coins, and will give one coin to the third most senior pirate and another coin to the most junior pirate.

If there were 2 pirates, pirate 2 being the most senior, he would just vote for himself and that would be 50% of the vote, so he's obviously going to keep all the money for himself. If there were 3 pirates, pirate 3 has to convince at least one other person to join in his plan. Pirate 3 would take 99 gold coins and give 1 coin to pirate 1. Pirate 1 knows if he does not vote for pirate 3, then he gets nothing, so obviously is going to vote for this plan. If there were 4 pirates, pirate 4 would give 1 coin to pirate 2, and pirate 2 knows if he does not vote for pirate 4, then he gets nothing, so obviously is going to vote for this plan.

As there are 5 pirates, pirates 1 and 3 had obviously better vote for the captain, or they face choosing nothing or risking a horrible death.

I tried for about a half hour (the amount of time it takes to drive home from work) to find a counter example.  I'm glad I stopped there:

Good thinking, All, you were completely right.  The proof also holds for points of discontinuity, you just have to adjust some words here and there.

Wait a minute.  How can you factor out cos(x)/|cos(x)|?  That isn't factoring our anything, that's completely changing the function.  When tan(x) is negative, there will be times when cos(x)/|cos(x)| is positive.  Thus, if such where the case:

tan(x) * cos(x)/|cos(x)| = negative * postive = negative.

But if we are to assume tan(x)*cos(x)/|cos(x)| = |tan(x)|, then it would be that negative = positive.

You can take a constant out of such integrals because constants don't change as x changes.  The same is not true for cos(x)/|cos(x)|.

In general, if you have:

integral of f(x)g(x)

You can not do:

f(x) times integral of g(x).

A simple example:

Let f(x) = x and g(x) = x.