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Determine the slope of the tangent to the graph of y=2x^2+3x at the general point whose x coordinate is a.
I have to use limits to solve this problem and I'm having trouble with the algebra involved. This is where I'm stuck:
lim 2x^2+3x-(2a^2-3a)
x->a x-a
Do I factor out the x and then factor out the a? Or do I factor out the 2 from the 2x^2 and the 2a^2 and then the 3 from the 3x^2 and 3a^2? I know the answer is 4x-3, I'm just having trouble getting there. Thanks!
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Ok, starting from
Therefore
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