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#1 2009-04-08 21:18:05

Angel Rox
Member
Registered: 2008-11-10
Posts: 15

need help urgently...

Q1 - Find the critical points of the function  f(x,y) = x^2 + 2y^2 - x^2y and then classify them into relative maxima, relative minima and saddle points.


Q2 - Let f(x,y) = xy - x - y + 3 and R is the triangular region with vertices (0, 0), (2, 0) and (0, 4). Find the interior and boundary points only at which the absolute extrema of f(x,y) can occur.

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#2 2009-04-09 23:59:47

ishaq027
Member
Registered: 2009-04-09
Posts: 1

Re: need help urgently...

Please give me quick Answer
Let f(x,y)=x^2+2y^2-x^2y  and then classify them into relative maxima, relative minima and saddle points

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#3 2009-04-10 00:09:46

ashfaq
Guest

Re: need help urgently...

Angel Rox wrote:

Q1 - Find the critical points of the function  f(x,y) = x^2 + 2y^2 - x^2y and then classify them into relative maxima, relative minima and saddle points.


Q2 - Let f(x,y) = xy - x - y + 3 and R is the triangular region with vertices (0, 0), (2, 0) and (0, 4). Find the interior and boundary points only at which the absolute extrema of f(x,y) can occur.

#4 2009-04-10 01:32:06

luca-deltodesco
Member
Registered: 2006-05-05
Posts: 1,470

Re: need help urgently...

----



----



which gives stationary points of (0,0) (2,1) (-2,1)

----

forming the hessian matrix:

----  first stationary points (0,0)


-> non degenerate


both eigenvalues are positive, so (0,0) is a local minimum

---- second stationary point (2,1)


-> non degenerate





one eigenvalue is negative, one is positive, so (2,1) is a saddle point

---- third stationary points (-2,1)


-> non degenerate


same eigenvalues as previous stationary point, so (-2,1) is also a saddle point:

--------


(0,0) is a local minimum
(2,1), (-2,1) are saddle points


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