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**soha****Real Member**- Registered: 2006-07-07
- Posts: 2,530

If x^2 = 5x then the value of x are

A) 0 B) 0 & 5 C) 5 D) 0 & - 5

2.The expressions with HCF & LCM as 4xy^2 & 8x^3y^5 is

A) 4x^2y^5 & 8x^3y^2 B) 4xy^5 & 8x^3y^2 C) 4x^2y^5 & 8xy^2 D) 4y^5 & 8y^2

3.Quadratic equation with roots ( 3 + or - root 2 ) is

A) x^2 + 6x 7 = 0 B) x^2 6x + 7 =0 C) x^2 + 6x 7 = 0 D) x^2 6x 7 = 0

4.In a graph , straight line intersects the parabola at(3,9) & (1, 1) Then the equation is

A) x^22x+3=0 B) x^2+2x3=0 C) x^23x+2=0 D) x^22x3=0

5.Relation between a cone and a cylinder with same radius and height is

A) cone = cylinder B) 3 cone = cylinder C) cone =3 cylinder D) All the above

6.The lateral surface area of a roller is 5sqm. Find the number of revolutions that it does

to cover a feild of 1000 sqm

A) 100 B) 200 C) 50 D) 500

please explain along with the answer

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**ZHero****Real Member**- Registered: 2008-06-08
- Posts: 1,889

*Last edited by ZHero (2010-03-21 21:20:52)*

If two or more thoughts intersect, there has to be a point!

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**ZHero****Real Member**- Registered: 2008-06-08
- Posts: 1,889

If two or more thoughts intersect, there has to be a point!

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**soha****Real Member**- Registered: 2006-07-07
- Posts: 2,530

in 3 . you got the sum and product by -b/a and c/a

"Let us realize that: the privilege to work is a gift, the power to work is a blessing, the love of work is success!"

- David O. McKay

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**ZHero****Real Member**- Registered: 2008-06-08
- Posts: 1,889

No!

The two roots are...

and

Now ADD them and MULTIPLY them to get SUM and PRODUCT respectively...

If two or more thoughts intersect, there has to be a point!

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**soha****Real Member**- Registered: 2006-07-07
- Posts: 2,530

ok.. had got confused ..

got it now

"Let us realize that: the privilege to work is a gift, the power to work is a blessing, the love of work is success!"

- David O. McKay

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**Monox D. I-Fly****Member**- From: Indonesia
- Registered: 2015-12-02
- Posts: 1,238

ZHero wrote:

I think it doesn't make sense. A quadratic equation with roots -3 and 1 would have 0 at their ordinates instead of 9 and 1 like what was asked in the question.

Actually I never watch Star Wars and not interested in it anyway, but I choose a Yoda card as my avatar in honor of our great friend bobbym who has passed away. May his adventurous soul rest in peace at heaven.

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