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How do you change variables properly to get the line integral of any f(x,y,z) on any curve C modeled by r(t)??? Im so lost!
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Hi calccrypto;
I am the worst in the world with line integrals. How about posting a specific problem and maybe we can get through it together.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
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Hi bobbym! I got this question:
C modeled by r(t) = (t, 3t^2, 6t^3)
and
f(x,y,z) = x y z^2
compute the line integral of f along C as modeled by r(t)
so far, i have only gotten r'(t) = (1, 6t, 18t^2) and f(t) = 18t^6. I dont know how to continue. all i know is the answer is 864/5
Last edited by calccrypto (2010-10-06 07:05:16)
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Hi;
How did you get 18t^6 for f(r(t))?
Did they give you some range for t?
Like maybe 0 <= t <= 1 ?
Take a look here for some general info that might help.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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i just replaced the components of r for (x,y,z) and multiplied.
and yep. I forgot to put in the limits, which are 0<= t <= 1 like you guessed
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Hi;
If I guessed the interval then you did not do f(r(t)) right. Want to try it again?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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i dont know how to continue at all
Visit calccrypto.wikidot.com for detailed descriptions of algorithms and other crypto related stuff (not much yet, so help would be appreciated).
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Hi;
This is what I did:
Please check the work as I have not done one of these in years and my notes on them are sketchy.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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oh.. thats what you meant in that previous post. wow. i fail. shoot me
Last edited by calccrypto (2010-10-06 12:46:45)
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Hi cal;
No shooting allowed here. Had my brother check it, he said this is a book problem that he remembers but he can not remember where.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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No wonder! I forgot to square the z component.
Visit calccrypto.wikidot.com for detailed descriptions of algorithms and other crypto related stuff (not much yet, so help would be appreciated).
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Hi;
Use this formula when you are given a line integral where everything has already been parametized like r(t).
It is all covered in the link I posted. This link here will provide more and probably what you will be doing soon.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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what happens if f returns a vector?
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Hi calccrypto;
I do not see how that can happen from the above formula.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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i meant a generic question. instead of xyz^2, say the output of f was something like (xy,yz,xz) or something. then what?
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Hi calccrypto;
You mean when you substitute x,y,z, in f(x,y,z)?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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no i meant instead of
f(x,y,x) = scalar value like xyz
the equation is
f(x,y,z) = vector, like (xy,yz,xz)
but i think i got it
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