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#1 2011-11-26 01:31:48
- Arnold Robin
- Guest
Math Challenge / Mystery
What 2 digit number has a value that is 6 times the sum of its digits?
#2 2011-11-26 01:38:09
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Math Challenge / Mystery
Hi Arnold Robin;
54.
Welcome to the forum.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#3 2011-11-26 01:42:32
- ArnoldRobin
- Member
- Registered: 2011-11-26
- Posts: 6
Re: Math Challenge / Mystery
thanks a lot, how did you solve it in a process.
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#4 2011-11-26 01:47:47
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Math Challenge / Mystery
Let a equal the first number and b equal the second number.
Subtract b from both sides.
Subtract 6 a from both sides.
b = 4 and a = 5. So the number is 10*5 + 4 = 54.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#5 2011-11-26 01:58:17
- ArnoldRobin
- Member
- Registered: 2011-11-26
- Posts: 6
Re: Math Challenge / Mystery
thank you so much for solving my homework. i still can't understand much algebra 'coz i'm just in grade III but our teacher always give us math challenges and this particular problem I just can't solve in a process. thanks a lot again.
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#6 2011-11-26 02:03:47
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Math Challenge / Mystery
Hi ArnoldRobin;
I hope you tried to do it on your own. I usually will not do homework for anyone because it is something that you must do on your own. I hope you understand that.
You say you are in the 3rd grade. You are at the perfect age for learning. I hope to see you in here in the future. Then I will give you problems to work on.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#7 2011-11-26 14:04:06
- ArnoldRobin
- Member
- Registered: 2011-11-26
- Posts: 6
Re: Math Challenge / Mystery
Hi Bobbym, I tried 12 times but the formula no longer work, need your help again.
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#8 2011-11-26 14:15:29
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Math Challenge / Mystery
What help do you need? Can you be more specific?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
#9 2011-11-26 14:45:37
- ArnoldRobin
- Member
- Registered: 2011-11-26
- Posts: 6
Re: Math Challenge / Mystery
What 2 digit number has a value that is 12 (or more or 100+) times the sum of its digits?
What about 3 digit number has a value that is 12 (or more or 100+) times the sum of its digits?
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#10 2011-11-26 14:48:40
- ArnoldRobin
- Member
- Registered: 2011-11-26
- Posts: 6
Re: Math Challenge / Mystery
Why 10a + 1b is used, why not 20a + 4b instead?
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#11 2011-11-26 15:50:20
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Math Challenge / Mystery
Because 10 a + b is how you represent a 2 digit number.
What 2 digit number has a value that is 12 (or more or 100+) times the sum of its digits?
It is not possible to have a 2 digit number that is 12 or more times the sum of its digits
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#12 2011-11-26 18:17:14
- ArnoldRobin
- Member
- Registered: 2011-11-26
- Posts: 6
Re: Math Challenge / Mystery
Hi Bobbym, it worked! Just being scared of the negative number:
10a + b = 12a + 12b
-2a = 11b
a=11; b=-2
10(11) - 2 = 108
1+0+8 = 9 x 12 = 108
Thank you so much for the enlightenment. You are so wonderful. God bless.
P.S. Hope you won't get fed up with other help I would need.
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#13 2011-11-26 22:43:45
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Math Challenge / Mystery
Hi ArnoldRobin;
I am happy that you found a solution by yourself. The idea you used made finding that one easy. Very good!
Hope you won't get fed up with other help I would need.
Post all you like.
Perhaps you will work on this problem:
What 3 digit number is 14 times the sum of its digits?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#14 2011-11-27 03:58:52
- kumara
- Member
- Registered: 2011-11-25
- Posts: 7
Re: Math Challenge / Mystery
54 am i right?
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#15 2011-11-27 05:32:30
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Math Challenge / Mystery
Hi kumara;
Yes, that is correct but not to mine!
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
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