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#1 2012-08-24 10:11:42
- anonimnystefy
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A custom Maxima Riemann sum function
Code:
integraten(f,a,b,n):=sum(ev(f,x=a+i*(b-a)/n)*(b-a)/n,i,0,n-1);
Last edited by anonimnystefy (2013-04-19 10:13:46)
The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón
#2 2012-08-25 07:00:01
- bobbym
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Re: A custom Maxima Riemann sum function
Hi;
What does ev do?
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#3 2012-08-25 07:02:56
- anonimnystefy
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Re: A custom Maxima Riemann sum function
ev(expresson in x, x=value) evaluates the expression at a specified value of the variable x (or any variable which the expression is given with).
The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón
#4 2012-08-25 17:33:46
- bobbym
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Re: A custom Maxima Riemann sum function
Hi anonimnystefy;
Nice, but please correct this line in your function:
Code:
s:s+ev(f,x=i)*(a-b)/n,
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.
#5 2012-08-25 20:09:12
- anonimnystefy
- Real Member
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Re: A custom Maxima Riemann sum function
Oh yeah. It should be b-a there.
The limit operator is just an excuse for doing something you know you can't.
“It's the subject that nobody knows anything about that we can all talk about!” ― Richard Feynman
“A secret's worth depends on the people from whom it must be kept.” ― Carlos Ruiz Zafón
#6 2012-08-25 20:23:56
- bobbym
- Administrator
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Re: A custom Maxima Riemann sum function
Hi;
That is exactly right.
In mathematics, you don't understand things. You just get used to them.
90% of mathematicians do not understand 90% of currently published mathematics.
I am willing to wager that over 75% of the new words that appeared were nothing more than spelling errors that caught on.