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**21122012****Member**- Registered: 2012-11-16
- Posts: 278

is error!

I live in Russia and I do not know many mathematical terms in English therefore I give the text in Russian

I live in Russia and I do not know many mathematical terms in English therefore I give the text in Russian

*Last edited by 21122012 (2012-11-16 14:35:11)*

**"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"**

** Thomas Ioannes Stiltes.** ...

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 94,634

Hi;

Why do you think that is an error?

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**21122012****Member**- Registered: 2012-11-16
- Posts: 278

Excuse I write by means of the automatic translator

**"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"**

** Thomas Ioannes Stiltes.** ...

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 94,634

Hi;

I am sorry but my Russian is limited to some chess terms. Much worse than your English.

But I still have to say that my answer in post #2 is correct, notation wise. Therefore your statement in post#1 is not.

Who is the author of those papers you have cited?

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**anonimnystefy****Real Member**- From: The Foundation
- Registered: 2011-05-23
- Posts: 15,919

I have a Russian to Serbian dictionary. Maybe I could translate the paper later today...

Here lies the reader who will never open this book. He is forever dead.

Taking a new step, uttering a new word, is what people fear most. ― Fyodor Dostoyevsky, Crime and Punishment

The knowledge of some things as a function of age is a delta function.

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 94,634

Hi;

Maybe you should wait until the OP comes back.

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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**bob bundy****Moderator**- Registered: 2010-06-20
- Posts: 6,914

hi

I haven't followed the text but the mathematics seems to simplify down to

(half way down the text)

and

(and at the end)

Since there are no given limits and 'a' is treated as a constant here, I don't see any contradiction.

The difference is just a constant of integration.

Bob

You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei

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**Fistfiz****Member**- Registered: 2012-07-20
- Posts: 33

21122012 wrote:

is error!

Hi endoftheworld,

I may be wrong, but I think stating that:

∫f(x)dx=F(x)+C

is an error, is itself a (logical) error. Because the indefinite integral is DEFINED AS the solution to the problem:

F'(x)=f(x)

It is the antiderivative, and what you gave is just the definition... does it make any sense to ask if is a definition right or wrong?

Saying that ∫f(x)dx=F(x)+C is an error seems to me like saying that it's wrong to put the ' to indicate the derivative...

I could have totally missed the point, maybe for example your paper says the defining the indefinite integral this way leads to some contradiction; in case i hope you can explain us.

30+2=28 (Mom's identity)

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**21122012****Member**- Registered: 2012-11-16
- Posts: 278

Closed

**"The conditions imposed on functions, become a source of difficulties which will manage to be avoided only by means of new researches about the principles of integral calculus"**

** Thomas Ioannes Stiltes.** ...

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**bobbym****Administrator**- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 94,634

Hi;

You wish to close the thread? Okay, I have closed it.

**In mathematics, you don't understand things. You just get used to them.**

**If it ain't broke, fix it until it is.**

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